Basic Math Examples

$- 11 + 10 (10 p - 2) = 10 (- 3 + 10 p)$

Step 1

Simplify $- 11 + 10 (10 p - 2)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$- 11 + 10 (10 p) + 10 \cdot - 2 = 10 (- 3 + 10 p)$

Step 1.1.2

Multiply $10$ by $10$ .

$- 11 + 100 p + 10 \cdot - 2 = 10 (- 3 + 10 p)$

Step 1.1.3

Multiply $10$ by $- 2$ .

$- 11 + 100 p - 20 = 10 (- 3 + 10 p)$

Step 1.2

Subtract $20$ from $- 11$ .

$100 p - 31 = 10 (- 3 + 10 p)$

Step 2

Simplify $10 (- 3 + 10 p)$ .

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Step 2.1

Apply the distributive property.

$100 p - 31 = 10 \cdot - 3 + 10 (10 p)$

Step 2.2

Multiply.

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Step 2.2.1

Multiply $10$ by $- 3$ .

$100 p - 31 = - 30 + 10 (10 p)$

Step 2.2.2

Multiply $10$ by $10$ .

$100 p - 31 = - 30 + 100 p$

Step 3

Move all terms containing $p$ to the left side of the equation.

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Step 3.1

Subtract $100 p$ from both sides of the equation.

$100 p - 31 - 100 p = - 30$

Step 3.2

Combine the opposite terms in $100 p - 31 - 100 p$ .

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Step 3.2.1

Subtract $100 p$ from $100 p$ .

$0 - 31 = - 30$

Step 3.2.2

Subtract $31$ from $0$ .

$- 31 = - 30$

Step 4

Since $- 31 \neq - 30$ , there are no solutions.

No solution