Basic Math Examples

$- \frac{3}{20} = m - \frac{7}{12}$

Step 1

Rewrite the equation as $m - \frac{7}{12} = - \frac{3}{20}$ .

$m - \frac{7}{12} = - \frac{3}{20}$

Step 2

Move all terms not containing $m$ to the right side of the equation.

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Step 2.1

Add $\frac{7}{12}$ to both sides of the equation.

$m = - \frac{3}{20} + \frac{7}{12}$

Step 2.2

To write $- \frac{3}{20}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$m = - \frac{3}{20} \cdot \frac{3}{3} + \frac{7}{12}$

Step 2.3

To write $\frac{7}{12}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$m = - \frac{3}{20} \cdot \frac{3}{3} + \frac{7}{12} \cdot \frac{5}{5}$

Step 2.4

Write each expression with a common denominator of $60$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.4.1

Multiply $\frac{3}{20}$ by $\frac{3}{3}$ .

$m = - \frac{3 \cdot 3}{20 \cdot 3} + \frac{7}{12} \cdot \frac{5}{5}$

Step 2.4.2

Multiply $20$ by $3$ .

$m = - \frac{3 \cdot 3}{60} + \frac{7}{12} \cdot \frac{5}{5}$

Step 2.4.3

Multiply $\frac{7}{12}$ by $\frac{5}{5}$ .

$m = - \frac{3 \cdot 3}{60} + \frac{7 \cdot 5}{12 \cdot 5}$

Step 2.4.4

Multiply $12$ by $5$ .

$m = - \frac{3 \cdot 3}{60} + \frac{7 \cdot 5}{60}$

Step 2.5

Combine the numerators over the common denominator.

$m = \frac{- 3 \cdot 3 + 7 \cdot 5}{60}$

Step 2.6

Simplify the numerator.

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Step 2.6.1

Multiply $- 3$ by $3$ .

$m = \frac{- 9 + 7 \cdot 5}{60}$

Step 2.6.2

Multiply $7$ by $5$ .

$m = \frac{- 9 + 35}{60}$

Step 2.6.3

Add $- 9$ and $35$ .

$m = \frac{26}{60}$

Step 2.7

Cancel the common factor of $26$ and $60$ .

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Step 2.7.1

Factor $2$ out of $26$ .

$m = \frac{2 (13)}{60}$

Step 2.7.2

Cancel the common factors.

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Step 2.7.2.1

Factor $2$ out of $60$ .

$m = \frac{2 \cdot 13}{2 \cdot 30}$

Step 2.7.2.2

Cancel the common factor.

$m = \frac{2 \cdot 13}{2 \cdot 30}$

Step 2.7.2.3

Rewrite the expression.

$m = \frac{13}{30}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$m = \frac{13}{30}$

Decimal Form:

$m = 0.4\overline{3}$