Basic Math Examples

$\frac{3}{4} y + \frac{1}{8} = \frac{3}{4} \cdot (y + 8)$

Step 1

Combine $\frac{3}{4}$ and $y$ .

$\frac{3 y}{4} + \frac{1}{8} = \frac{3}{4} \cdot (y + 8)$

Step 2

Simplify $\frac{3}{4} \cdot (y + 8)$ .

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Step 2.1

Apply the distributive property.

$\frac{3 y}{4} + \frac{1}{8} = \frac{3}{4} y + \frac{3}{4} \cdot 8$

Step 2.2

Combine $\frac{3}{4}$ and $y$ .

$\frac{3 y}{4} + \frac{1}{8} = \frac{3 y}{4} + \frac{3}{4} \cdot 8$

Step 2.3

Cancel the common factor of $4$ .

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Step 2.3.1

Factor $4$ out of $8$ .

$\frac{3 y}{4} + \frac{1}{8} = \frac{3 y}{4} + \frac{3}{4} \cdot (4 (2))$

Step 2.3.2

Cancel the common factor.

$\frac{3 y}{4} + \frac{1}{8} = \frac{3 y}{4} + \frac{3}{4} \cdot (4 \cdot 2)$

Step 2.3.3

Rewrite the expression.

$\frac{3 y}{4} + \frac{1}{8} = \frac{3 y}{4} + 3 \cdot 2$

Step 2.4

Multiply $3$ by $2$ .

$\frac{3 y}{4} + \frac{1}{8} = \frac{3 y}{4} + 6$

Step 3

Move all terms containing $y$ to the left side of the equation.

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Step 3.1

Subtract $\frac{3 y}{4}$ from both sides of the equation.

$\frac{3 y}{4} + \frac{1}{8} - \frac{3 y}{4} = 6$

Step 3.2

Combine the opposite terms in $\frac{3 y}{4} + \frac{1}{8} - \frac{3 y}{4}$ .

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Step 3.2.1

Subtract $\frac{3 y}{4}$ from $\frac{3 y}{4}$ .

$0 + \frac{1}{8} = 6$

Step 3.2.2

Add $0$ and $\frac{1}{8}$ .

$\frac{1}{8} = 6$

Step 4

Since $\frac{1}{8} \neq 6$ , there are no solutions.

No solution