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Solve for t y=t^(2-4t)

$y = t^{2 - 4 t}$

Step 1

Rewrite the equation as $t^{2 - 4 t} = y$ .

$t^{2 - 4 t} = y$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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