Basic Math Examples

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \div \frac{6 a^{2} + 10 a}{1 - 6 a + 9 a^{2}}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{1 - 6 a + 9 a^{2}}{6 a^{2} + 10 a}$

Step 2

Factor using the perfect square rule.

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Step 2.1

Rewrite $1$ as $1^{2}$ .

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{1^{2} - 6 a + 9 a^{2}}{6 a^{2} + 10 a}$

Step 2.2

Rewrite $9 a^{2}$ as ${(3 a)}^{2}$ .

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{1^{2} - 6 a + {(3 a)}^{2}}{6 a^{2} + 10 a}$

Step 2.3

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$6 a = 2 \cdot 1 \cdot (3 a)$

Step 2.4

Rewrite the polynomial.

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{1^{2} - 2 \cdot 1 \cdot (3 a) + {(3 a)}^{2}}{6 a^{2} + 10 a}$

Step 2.5

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = 1$ and $b = 3 a$ .

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{{(1 - 3 a)}^{2}}{6 a^{2} + 10 a}$

Step 3

Factor $2 a$ out of $6 a^{2} + 10 a$ .

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Step 3.1

Factor $2 a$ out of $6 a^{2}$ .

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a) + 10 a}$

Step 3.2

Factor $2 a$ out of $10 a$ .

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a) + 2 a (5)}$

Step 3.3

Factor $2 a$ out of $2 a (3 a) + 2 a (5)$ .

$(\frac{2 a}{3 a + 1} + \frac{3 a}{1 - 3 a}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 4

To write $\frac{2 a}{3 a + 1}$ as a fraction with a common denominator, multiply by $\frac{1 - 3 a}{1 - 3 a}$ .

$(\frac{2 a}{3 a + 1} \cdot \frac{1 - 3 a}{1 - 3 a} + \frac{3 a}{1 - 3 a}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 5

To write $\frac{3 a}{1 - 3 a}$ as a fraction with a common denominator, multiply by $\frac{3 a + 1}{3 a + 1}$ .

$(\frac{2 a}{3 a + 1} \cdot \frac{1 - 3 a}{1 - 3 a} + \frac{3 a}{1 - 3 a} \cdot \frac{3 a + 1}{3 a + 1}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 6

Write each expression with a common denominator of $(3 a + 1) (1 - 3 a)$ , by multiplying each by an appropriate factor of $1$ .

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Step 6.1

Multiply $\frac{2 a}{3 a + 1}$ by $\frac{1 - 3 a}{1 - 3 a}$ .

$(\frac{2 a (1 - 3 a)}{(3 a + 1) (1 - 3 a)} + \frac{3 a}{1 - 3 a} \cdot \frac{3 a + 1}{3 a + 1}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 6.2

Multiply $\frac{3 a}{1 - 3 a}$ by $\frac{3 a + 1}{3 a + 1}$ .

$(\frac{2 a (1 - 3 a)}{(3 a + 1) (1 - 3 a)} + \frac{3 a (3 a + 1)}{(1 - 3 a) (3 a + 1)}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 6.3

Reorder the factors of $(3 a + 1) (1 - 3 a)$ .

$(\frac{2 a (1 - 3 a)}{(1 - 3 a) (3 a + 1)} + \frac{3 a (3 a + 1)}{(1 - 3 a) (3 a + 1)}) \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 7

Combine the numerators over the common denominator.

$\frac{2 a (1 - 3 a) + 3 a (3 a + 1)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8

Simplify the numerator.

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Step 8.1

Factor $a$ out of $2 a (1 - 3 a) + 3 a (3 a + 1)$ .

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Step 8.1.1

Factor $a$ out of $2 a (1 - 3 a)$ .

$\frac{a (2 (1 - 3 a)) + 3 a (3 a + 1)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.1.2

Factor $a$ out of $3 a (3 a + 1)$ .

$\frac{a (2 (1 - 3 a)) + a (3 (3 a + 1))}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.1.3

Factor $a$ out of $a (2 (1 - 3 a)) + a (3 (3 a + 1))$ .

$\frac{a (2 (1 - 3 a) + 3 (3 a + 1))}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.2

Apply the distributive property.

$\frac{a (2 \cdot 1 + 2 (- 3 a) + 3 (3 a + 1))}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.3

Multiply $2$ by $1$ .

$\frac{a (2 + 2 (- 3 a) + 3 (3 a + 1))}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.4

Multiply $- 3$ by $2$ .

$\frac{a (2 - 6 a + 3 (3 a + 1))}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.5

Apply the distributive property.

$\frac{a (2 - 6 a + 3 (3 a) + 3 \cdot 1)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.6

Multiply $3$ by $3$ .

$\frac{a (2 - 6 a + 9 a + 3 \cdot 1)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.7

Multiply $3$ by $1$ .

$\frac{a (2 - 6 a + 9 a + 3)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.8

Add $2$ and $3$ .

$\frac{a (- 6 a + 9 a + 5)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 8.9

Add $- 6 a$ and $9 a$ .

$\frac{a (3 a + 5)}{(1 - 3 a) (3 a + 1)} \cdot \frac{{(1 - 3 a)}^{2}}{2 a (3 a + 5)}$

Step 9

Simplify terms.

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Step 9.1

Combine.

$\frac{a (3 a + 5) {(1 - 3 a)}^{2}}{(1 - 3 a) (3 a + 1) (2 a (3 a + 5))}$

Step 9.2

Cancel the common factor of $a$ .

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Step 9.2.1

Cancel the common factor.

$\frac{a (3 a + 5) {(1 - 3 a)}^{2}}{(1 - 3 a) (3 a + 1) (2 a (3 a + 5))}$

Step 9.2.2

Rewrite the expression.

$\frac{(3 a + 5) {(1 - 3 a)}^{2}}{(1 - 3 a) (3 a + 1) (2 (3 a + 5))}$

Step 9.3

Cancel the common factor of $3 a + 5$ .

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Step 9.3.1

Cancel the common factor.

$\frac{(3 a + 5) {(1 - 3 a)}^{2}}{(1 - 3 a) (3 a + 1) (2 (3 a + 5))}$

Step 9.3.2

Rewrite the expression.

$\frac{{(1 - 3 a)}^{2}}{(1 - 3 a) (3 a + 1) \cdot (2)}$

Step 9.4

Cancel the common factor of ${(1 - 3 a)}^{2}$ and $1 - 3 a$ .

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Step 9.4.1

Factor $1 - 3 a$ out of ${(1 - 3 a)}^{2}$ .

$\frac{(1 - 3 a) (1 - 3 a)}{(1 - 3 a) (3 a + 1) \cdot (2)}$

Step 9.4.2

Cancel the common factors.

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Step 9.4.2.1

Factor $1 - 3 a$ out of $(1 - 3 a) (3 a + 1) \cdot (2)$ .

$\frac{(1 - 3 a) (1 - 3 a)}{(1 - 3 a) ((3 a + 1) \cdot (2))}$

Step 9.4.2.2

Cancel the common factor.

$\frac{(1 - 3 a) (1 - 3 a)}{(1 - 3 a) ((3 a + 1) \cdot (2))}$

Step 9.4.2.3

Rewrite the expression.

$\frac{1 - 3 a}{(3 a + 1) \cdot (2)}$

Step 9.5

Move $2$ to the left of $3 a + 1$ .

$\frac{1 - 3 a}{2 (3 a + 1)}$