Basic Math Examples

15 \cdot 0.7 = 0.1 y + 0.1 (15 - y)

$15 \cdot 0.7 = 0.1 y + 0.1 (15 - y)$

Step 1

Rewrite the equation as

0.1 y + 0.1 (15 - y) = 15 \cdot 0.7

$0.1 y + 0.1 (15 - y) = 15 \cdot 0.7$ .

0.1 y + 0.1 (15 - y) = 15 \cdot 0.7

$0.1 y + 0.1 (15 - y) = 15 \cdot 0.7$

Step 2

Simplify

0.1 y + 0.1 (15 - y)

$0.1 y + 0.1 (15 - y)$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

0.1 y + 0.1 \cdot 15 + 0.1 (- y) = 15 \cdot 0.7

$0.1 y + 0.1 \cdot 15 + 0.1 (- y) = 15 \cdot 0.7$

Step 2.1.2

Multiply

0.1

$0.1$ by

15

$15$ .

0.1 y + 1.5 + 0.1 (- y) = 15 \cdot 0.7

$0.1 y + 1.5 + 0.1 (- y) = 15 \cdot 0.7$

Step 2.1.3

Multiply

- 1

$- 1$ by

0.1

$0.1$ .

0.1 y + 1.5 - 0.1 y = 15 \cdot 0.7

$0.1 y + 1.5 - 0.1 y = 15 \cdot 0.7$

0.1 y + 1.5 - 0.1 y = 15 \cdot 0.7

$0.1 y + 1.5 - 0.1 y = 15 \cdot 0.7$

Step 2.2

Simplify by adding terms.

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Step 2.2.1

Subtract

0.1 y

$0.1 y$ from

0.1 y

$0.1 y$ .

0 y + 1.5 = 15 \cdot 0.7

$0 y + 1.5 = 15 \cdot 0.7$

Step 2.2.2

Simplify the expression.

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Step 2.2.2.1

Multiply

0

$0$ by

y

$y$ .

0 + 1.5 = 15 \cdot 0.7

$0 + 1.5 = 15 \cdot 0.7$

Step 2.2.2.2

Add

0

$0$ and

1.5

$1.5$ .

1.5 = 15 \cdot 0.7

$1.5 = 15 \cdot 0.7$

1.5 = 15 \cdot 0.7

$1.5 = 15 \cdot 0.7$

1.5 = 15 \cdot 0.7

$1.5 = 15 \cdot 0.7$

1.5 = 15 \cdot 0.7

$1.5 = 15 \cdot 0.7$

Step 3

Multiply

15

$15$ by

0.7

$0.7$ .

1.5 = 10.5

$1.5 = 10.5$

Step 4

Since

1.5 \neq 10.5

$1.5 \neq 10.5$ , there are no solutions.

No solution

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$