Basic Math Examples

$4 (- 3 y + 4) = - 2 (6 y - 8)$

Step 1

Simplify $4 (- 3 y + 4)$ .

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Step 1.1

Rewrite.

$0 + 0 + 4 (- 3 y + 4) = - 2 (6 y - 8)$

Step 1.2

Simplify by adding zeros.

$4 (- 3 y + 4) = - 2 (6 y - 8)$

Step 1.3

Apply the distributive property.

$4 (- 3 y) + 4 \cdot 4 = - 2 (6 y - 8)$

Step 1.4

Multiply.

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Step 1.4.1

Multiply $- 3$ by $4$ .

$- 12 y + 4 \cdot 4 = - 2 (6 y - 8)$

Step 1.4.2

Multiply $4$ by $4$ .

$- 12 y + 16 = - 2 (6 y - 8)$

Step 2

Simplify $- 2 (6 y - 8)$ .

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Step 2.1

Apply the distributive property.

$- 12 y + 16 = - 2 (6 y) - 2 \cdot - 8$

Step 2.2

Multiply.

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Step 2.2.1

Multiply $6$ by $- 2$ .

$- 12 y + 16 = - 12 y - 2 \cdot - 8$

Step 2.2.2

Multiply $- 2$ by $- 8$ .

$- 12 y + 16 = - 12 y + 16$

Step 3

Move all terms containing $y$ to the left side of the equation.

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Step 3.1

Add $12 y$ to both sides of the equation.

$- 12 y + 16 + 12 y = 16$

Step 3.2

Combine the opposite terms in $- 12 y + 16 + 12 y$ .

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Step 3.2.1

Add $- 12 y$ and $12 y$ .

$0 + 16 = 16$

Step 3.2.2

Add $0$ and $16$ .

$16 = 16$

Step 4

Since $16 = 16$ , the equation will always be true for any value of $y$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$