Basic Math Examples

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\begin{matrix} b_{1} = & 8 b_{2} = & 7 h = & 12 \end{matrix}

$\begin{array}{r} b_{1} = & 8 \\ b_{2} = & 7 \\ h = & 12 \end{array}$

Step 1

The area of a trapezoid is equal to

\frac{1}{2}

$\frac{1}{2}$ times the height times the sum of the bases

b_{1} + b_{2}

$b_{1} + b_{2}$ .

\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height

h = 12

$h = 12$ and bases (

b_{1} = 8

$b_{1} = 8$ and

b_{2} = 7

$b_{2} = 7$ ) into the formula for the area of a trapezoid.

\frac{1}{2} \cdot 12 \cdot (8 + 7)

$\frac{1}{2} \cdot 12 \cdot (8 + 7)$

Step 3

Cancel the common factor of

2

$2$ .

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Step 3.1

Factor

2

$2$ out of

12

$12$ .

\frac{1}{2} \cdot (2 (6)) \cdot (8 + 7)

$\frac{1}{2} \cdot (2 (6)) \cdot (8 + 7)$

Step 3.2

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 6) \cdot (8 + 7)$

Step 3.3

Rewrite the expression.

$6 \cdot (8 + 7)$

Step 4

Simplify the expression.

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Step 4.1

Add

$8$ and

$7$ .

$6 \cdot 15$

Step 4.2

Multiply

$6$ by

$15$ .

$90$