Basic Math Examples

Solve for p 5p-9=2p+12
5p-9=2p+125p9=2p+12
Step 1
Move all terms containing pp to the left side of the equation.
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Step 1.1
Subtract 2p2p from both sides of the equation.
5p-9-2p=125p92p=12
Step 1.2
Subtract 2p2p from 5p5p.
3p-9=123p9=12
3p-9=123p9=12
Step 2
Move all terms not containing pp to the right side of the equation.
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Step 2.1
Add 99 to both sides of the equation.
3p=12+93p=12+9
Step 2.2
Add 1212 and 99.
3p=213p=21
3p=213p=21
Step 3
Divide each term in 3p=213p=21 by 33 and simplify.
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Step 3.1
Divide each term in 3p=213p=21 by 33.
3p3=2133p3=213
Step 3.2
Simplify the left side.
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Step 3.2.1
Cancel the common factor of 33.
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Step 3.2.1.1
Cancel the common factor.
3p3=213
Step 3.2.1.2
Divide p by 1.
p=213
p=213
p=213
Step 3.3
Simplify the right side.
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Step 3.3.1
Divide 21 by 3.
p=7
p=7
p=7
 [x2  12  π  xdx ]