Basic Math Examples

$\frac{1}{4} \cdot (60 + 16 s) = 15 + 4 s$

Step 1

Simplify $\frac{1}{4} \cdot (60 + 16 s)$ .

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Step 1.1

Rewrite.

$0 + 0 + \frac{1}{4} \cdot (60 + 16 s) = 15 + 4 s$

Step 1.2

Simplify by adding zeros.

$\frac{1}{4} \cdot (60 + 16 s) = 15 + 4 s$

Step 1.3

Apply the distributive property.

$\frac{1}{4} \cdot 60 + \frac{1}{4} (16 s) = 15 + 4 s$

Step 1.4

Cancel the common factor of $4$ .

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Step 1.4.1

Factor $4$ out of $60$ .

$\frac{1}{4} \cdot (4 (15)) + \frac{1}{4} (16 s) = 15 + 4 s$

Step 1.4.2

Cancel the common factor.

$\frac{1}{4} \cdot (4 \cdot 15) + \frac{1}{4} (16 s) = 15 + 4 s$

Step 1.4.3

Rewrite the expression.

$15 + \frac{1}{4} (16 s) = 15 + 4 s$

Step 1.5

Cancel the common factor of $4$ .

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Step 1.5.1

Factor $4$ out of $16 s$ .

$15 + \frac{1}{4} (4 (4 s)) = 15 + 4 s$

Step 1.5.2

Cancel the common factor.

$15 + \frac{1}{4} (4 (4 s)) = 15 + 4 s$

Step 1.5.3

Rewrite the expression.

$15 + 4 s = 15 + 4 s$

Step 2

Move all terms containing $s$ to the left side of the equation.

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Step 2.1

Subtract $4 s$ from both sides of the equation.

$15 + 4 s - 4 s = 15$

Step 2.2

Combine the opposite terms in $15 + 4 s - 4 s$ .

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Step 2.2.1

Subtract $4 s$ from $4 s$ .

$15 + 0 = 15$

Step 2.2.2

Add $15$ and $0$ .

$15 = 15$

Step 3

Since $15 = 15$ , the equation will always be true for any value of $s$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$