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Solve for y p(-7)=y^3-y

$p (- 7) = y^{3} - y$

Step 1

Rewrite the equation as $y^{3} - y = p (- 7)$ .

$y^{3} - y = p (- 7)$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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