Basic Math Examples

$- \frac{5}{3 u} - 3 = \frac{3}{2} u + \frac{7}{4}$

Step 1

Combine $\frac{3}{2}$ and $u$ .

$- \frac{5}{3 u} - 3 = \frac{3 u}{2} + \frac{7}{4}$

Step 2

Move all terms not containing $u$ to the right side of the equation.

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Step 2.1

Add $3$ to both sides of the equation.

$- \frac{5}{3 u} = \frac{3 u}{2} + \frac{7}{4} + 3$

Step 2.2

To write $3$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{5}{3 u} = \frac{3 u}{2} + \frac{7}{4} + 3 \cdot \frac{4}{4}$

Step 2.3

Combine $3$ and $\frac{4}{4}$ .

$- \frac{5}{3 u} = \frac{3 u}{2} + \frac{7}{4} + \frac{3 \cdot 4}{4}$

Step 2.4

Combine the numerators over the common denominator.

$- \frac{5}{3 u} = \frac{3 u}{2} + \frac{7 + 3 \cdot 4}{4}$

Step 2.5

Simplify the numerator.

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Step 2.5.1

Multiply $3$ by $4$ .

$- \frac{5}{3 u} = \frac{3 u}{2} + \frac{7 + 12}{4}$

Step 2.5.2

Add $7$ and $12$ .

$- \frac{5}{3 u} = \frac{3 u}{2} + \frac{19}{4}$

Step 3

Find the LCD of the terms in the equation.

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Step 3.1

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$3 u, 2, 4$

Step 3.2

Since $3 u, 2, 4$ contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $3, 2, 4$ then find LCM for the variable part $u^{1}$ .

Step 3.3

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

Step 3.4

Since $3$ has no factors besides $1$ and $3$ .

$3$ is a prime number

Step 3.5

Since $2$ has no factors besides $1$ and $2$ .

$2$ is a prime number

Step 3.6

$4$ has factors of $2$ and $2$ .

$2 \cdot 2$

Step 3.7

The LCM of $3, 2, 4$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$2 \cdot 2 \cdot 3$

Step 3.8

Multiply $2 \cdot 2 \cdot 3$ .

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Step 3.8.1

Multiply $2$ by $2$ .

$4 \cdot 3$

Step 3.8.2

Multiply $4$ by $3$ .

$12$

Step 3.9

The factor for $u^{1}$ is $u$ itself.

$u^{1} = u$

$u$ occurs $1$ time.

Step 3.10

The LCM of $u^{1}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$u$

Step 3.11

The LCM for $3 u, 2, 4$ is the numeric part $12$ multiplied by the variable part.

$12 u$

Step 4

Multiply each term in $- \frac{5}{3 u} = \frac{3 u}{2} + \frac{19}{4}$ by $12 u$ to eliminate the fractions.

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Step 4.1

Multiply each term in $- \frac{5}{3 u} = \frac{3 u}{2} + \frac{19}{4}$ by $12 u$ .

$- \frac{5}{3 u} (12 u) = \frac{3 u}{2} (12 u) + \frac{19}{4} (12 u)$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $3 u$ .

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Step 4.2.1.1

Move the leading negative in $- \frac{5}{3 u}$ into the numerator.

$\frac{- 5}{3 u} (12 u) = \frac{3 u}{2} (12 u) + \frac{19}{4} (12 u)$

Step 4.2.1.2

Factor $3 u$ out of $12 u$ .

$\frac{- 5}{3 u} (3 u (4)) = \frac{3 u}{2} (12 u) + \frac{19}{4} (12 u)$

Step 4.2.1.3

Cancel the common factor.

$\frac{- 5}{3 u} (3 u \cdot 4) = \frac{3 u}{2} (12 u) + \frac{19}{4} (12 u)$

Step 4.2.1.4

Rewrite the expression.

$- 5 \cdot 4 = \frac{3 u}{2} (12 u) + \frac{19}{4} (12 u)$

Step 4.2.2

Multiply $- 5$ by $4$ .

$- 20 = \frac{3 u}{2} (12 u) + \frac{19}{4} (12 u)$

Step 4.3

Simplify the right side.

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Step 4.3.1

Simplify each term.

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Step 4.3.1.1

Rewrite using the commutative property of multiplication.

$- 20 = 12 \frac{3 u}{2} u + \frac{19}{4} (12 u)$

Step 4.3.1.2

Cancel the common factor of $2$ .

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Step 4.3.1.2.1

Factor $2$ out of $12$ .

$- 20 = 2 (6) \frac{3 u}{2} u + \frac{19}{4} (12 u)$

Step 4.3.1.2.2

Cancel the common factor.

$- 20 = 2 \cdot 6 \frac{3 u}{2} u + \frac{19}{4} (12 u)$

Step 4.3.1.2.3

Rewrite the expression.

$- 20 = 6 (3 u) u + \frac{19}{4} (12 u)$

Step 4.3.1.3

Multiply $3$ by $6$ .

$- 20 = 18 u \cdot u + \frac{19}{4} (12 u)$

Step 4.3.1.4

Multiply $u$ by $u$ by adding the exponents.

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Step 4.3.1.4.1

Move $u$ .

$- 20 = 18 (u \cdot u) + \frac{19}{4} (12 u)$

Step 4.3.1.4.2

Multiply $u$ by $u$ .

$- 20 = 18 u^{2} + \frac{19}{4} (12 u)$

Step 4.3.1.5

Cancel the common factor of $4$ .

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Step 4.3.1.5.1

Factor $4$ out of $12 u$ .

$- 20 = 18 u^{2} + \frac{19}{4} (4 (3 u))$

Step 4.3.1.5.2

Cancel the common factor.

$- 20 = 18 u^{2} + \frac{19}{4} (4 (3 u))$

Step 4.3.1.5.3

Rewrite the expression.

$- 20 = 18 u^{2} + 19 (3 u)$

Step 4.3.1.6

Multiply $3$ by $19$ .

$- 20 = 18 u^{2} + 57 u$

Step 5

Solve the equation.

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Step 5.1

Rewrite the equation as $18 u^{2} + 57 u = - 20$ .

$18 u^{2} + 57 u = - 20$

Step 5.2

Add $20$ to both sides of the equation.

$18 u^{2} + 57 u + 20 = 0$

Step 5.3

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 5.4

Substitute the values $a = 18$ , $b = 57$ , and $c = 20$ into the quadratic formula and solve for $u$ .

$\frac{- 57 \pm \sqrt{57^{2} - 4 \cdot (18 \cdot 20)}}{2 \cdot 18}$

Step 5.5

Simplify.

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Step 5.5.1

Simplify the numerator.

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Step 5.5.1.1

Raise $57$ to the power of $2$ .

$u = \frac{- 57 \pm \sqrt{3249 - 4 \cdot 18 \cdot 20}}{2 \cdot 18}$

Step 5.5.1.2

Multiply $- 4 \cdot 18 \cdot 20$ .

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Step 5.5.1.2.1

Multiply $- 4$ by $18$ .

$u = \frac{- 57 \pm \sqrt{3249 - 72 \cdot 20}}{2 \cdot 18}$

Step 5.5.1.2.2

Multiply $- 72$ by $20$ .

$u = \frac{- 57 \pm \sqrt{3249 - 1440}}{2 \cdot 18}$

Step 5.5.1.3

Subtract $1440$ from $3249$ .

$u = \frac{- 57 \pm \sqrt{1809}}{2 \cdot 18}$

Step 5.5.1.4

Rewrite $1809$ as $3^{2} \cdot 201$ .

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Step 5.5.1.4.1

Factor $9$ out of $1809$ .

$u = \frac{- 57 \pm \sqrt{9 (201)}}{2 \cdot 18}$

Step 5.5.1.4.2

Rewrite $9$ as $3^{2}$ .

$u = \frac{- 57 \pm \sqrt{3^{2} \cdot 201}}{2 \cdot 18}$

Step 5.5.1.5

Pull terms out from under the radical.

$u = \frac{- 57 \pm 3 \sqrt{201}}{2 \cdot 18}$

Step 5.5.2

Multiply $2$ by $18$ .

$u = \frac{- 57 \pm 3 \sqrt{201}}{36}$

Step 5.5.3

Simplify $\frac{- 57 \pm 3 \sqrt{201}}{36}$ .

$u = \frac{- 19 \pm \sqrt{201}}{12}$

Step 5.6

The final answer is the combination of both solutions.

$u = - \frac{19 - \sqrt{201}}{12}, - \frac{19 + \sqrt{201}}{12}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$u = - \frac{19 - \sqrt{201}}{12}, - \frac{19 + \sqrt{201}}{12}$

Decimal Form:

$u = - 0.40187942 \dots, - 2.76478723 \dots$