Basic Math Examples

Solve for y y(11-y)=30
y(11-y)=30
Step 1
Simplify y(11-y).
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Step 1.1
Simplify by multiplying through.
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Step 1.1.1
Apply the distributive property.
y11+y(-y)=30
Step 1.1.2
Reorder.
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Step 1.1.2.1
Move 11 to the left of y.
11y+y(-y)=30
Step 1.1.2.2
Rewrite using the commutative property of multiplication.
11y-yy=30
11y-yy=30
11y-yy=30
Step 1.2
Multiply y by y by adding the exponents.
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Step 1.2.1
Move y.
11y-(yy)=30
Step 1.2.2
Multiply y by y.
11y-y2=30
11y-y2=30
11y-y2=30
Step 2
Subtract 30 from both sides of the equation.
11y-y2-30=0
Step 3
Factor the left side of the equation.
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Step 3.1
Factor -1 out of 11y-y2-30.
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Step 3.1.1
Reorder 11y and -y2.
-y2+11y-30=0
Step 3.1.2
Factor -1 out of -y2.
-(y2)+11y-30=0
Step 3.1.3
Factor -1 out of 11y.
-(y2)-(-11y)-30=0
Step 3.1.4
Rewrite -30 as -1(30).
-(y2)-(-11y)-130=0
Step 3.1.5
Factor -1 out of -(y2)-(-11y).
-(y2-11y)-130=0
Step 3.1.6
Factor -1 out of -(y2-11y)-1(30).
-(y2-11y+30)=0
-(y2-11y+30)=0
Step 3.2
Factor.
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Step 3.2.1
Factor y2-11y+30 using the AC method.
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Step 3.2.1.1
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 30 and whose sum is -11.
-6,-5
Step 3.2.1.2
Write the factored form using these integers.
-((y-6)(y-5))=0
-((y-6)(y-5))=0
Step 3.2.2
Remove unnecessary parentheses.
-(y-6)(y-5)=0
-(y-6)(y-5)=0
-(y-6)(y-5)=0
Step 4
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
y-6=0
y-5=0
Step 5
Set y-6 equal to 0 and solve for y.
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Step 5.1
Set y-6 equal to 0.
y-6=0
Step 5.2
Add 6 to both sides of the equation.
y=6
y=6
Step 6
Set y-5 equal to 0 and solve for y.
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Step 6.1
Set y-5 equal to 0.
y-5=0
Step 6.2
Add 5 to both sides of the equation.
y=5
y=5
Step 7
The final solution is all the values that make -(y-6)(y-5)=0 true.
y=6,5
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