Basic Math Examples

 $\begin{array}{r} h = & 2 \\ r = & 1 \end{array}$

Step 1

The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of $π \cdot r^{2}$ , plus the area of the side. The area of the side is equal to the area of a rectangle with length $2 π r$ (the circumference of the base) times the height.

$2 π \cdot {(r a d i u s)}^{2} + 2 π \cdot (r a d i u s) \cdot (h e i g h t)$

Step 2

Substitute the values of the radius $r = 1$ and height $h = 2$ into the formula. Pi $π$ is approximately equal to $3.14$ .

$2 (π) {(1)}^{2} + 2 (π) (1) (2)$

Step 3

Simplify each term.

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Step 3.1

One to any power is one.

$2 π \cdot 1 + 2 (π) (1) (2)$

Step 3.2

Multiply $2$ by $1$ .

$2 π + 2 (π) (1) (2)$

Step 3.3

Multiply $2$ by $1$ .

$2 π + 2 π \cdot 2$

Step 3.4

Multiply $2$ by $2$ .

$2 π + 4 π$

Step 4

Add $2 π$ and $4 π$ .

$6 π$

Step 5

The result can be shown in multiple forms.

Exact Form:

$6 π$

Decimal Form:

$18.84955592 \dots$