Basic Math Examples

$8 y + 4 (4 y - 3) = 4 (6 y + 4) - 4$

Step 1

Simplify $8 y + 4 (4 y - 3)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$8 y + 4 (4 y) + 4 \cdot - 3 = 4 (6 y + 4) - 4$

Step 1.1.2

Multiply $4$ by $4$ .

$8 y + 16 y + 4 \cdot - 3 = 4 (6 y + 4) - 4$

Step 1.1.3

Multiply $4$ by $- 3$ .

$8 y + 16 y - 12 = 4 (6 y + 4) - 4$

Step 1.2

Add $8 y$ and $16 y$ .

$24 y - 12 = 4 (6 y + 4) - 4$

Step 2

Simplify $4 (6 y + 4) - 4$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$24 y - 12 = 4 (6 y) + 4 \cdot 4 - 4$

Step 2.1.2

Multiply $6$ by $4$ .

$24 y - 12 = 24 y + 4 \cdot 4 - 4$

Step 2.1.3

Multiply $4$ by $4$ .

$24 y - 12 = 24 y + 16 - 4$

Step 2.2

Subtract $4$ from $16$ .

$24 y - 12 = 24 y + 12$

Step 3

Move all terms containing $y$ to the left side of the equation.

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Step 3.1

Subtract $24 y$ from both sides of the equation.

$24 y - 12 - 24 y = 12$

Step 3.2

Combine the opposite terms in $24 y - 12 - 24 y$ .

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Step 3.2.1

Subtract $24 y$ from $24 y$ .

$0 - 12 = 12$

Step 3.2.2

Subtract $12$ from $0$ .

$- 12 = 12$

Step 4

Since $- 12 \neq 12$ , there are no solutions.

No solution