Basic Math Examples

$15 x + 6 y = 20$

Step 1

Subtract $15 x$ from both sides of the equation.

$6 y = 20 - 15 x$

Step 2

Divide each term in $6 y = 20 - 15 x$ by $6$ and simplify.

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Step 2.1

Divide each term in $6 y = 20 - 15 x$ by $6$ .

$\frac{6 y}{6} = \frac{20}{6} + \frac{- 15 x}{6}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $6$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{6 y}{6} = \frac{20}{6} + \frac{- 15 x}{6}$

Step 2.2.1.2

Divide $y$ by $1$ .

$y = \frac{20}{6} + \frac{- 15 x}{6}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Cancel the common factor of $20$ and $6$ .

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Step 2.3.1.1.1

Factor $2$ out of $20$ .

$y = \frac{2 (10)}{6} + \frac{- 15 x}{6}$

Step 2.3.1.1.2

Cancel the common factors.

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Step 2.3.1.1.2.1

Factor $2$ out of $6$ .

$y = \frac{2 \cdot 10}{2 \cdot 3} + \frac{- 15 x}{6}$

Step 2.3.1.1.2.2

Cancel the common factor.

$y = \frac{2 \cdot 10}{2 \cdot 3} + \frac{- 15 x}{6}$

Step 2.3.1.1.2.3

Rewrite the expression.

$y = \frac{10}{3} + \frac{- 15 x}{6}$

Step 2.3.1.2

Cancel the common factor of $- 15$ and $6$ .

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Step 2.3.1.2.1

Factor $3$ out of $- 15 x$ .

$y = \frac{10}{3} + \frac{3 (- 5 x)}{6}$

Step 2.3.1.2.2

Cancel the common factors.

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Step 2.3.1.2.2.1

Factor $3$ out of $6$ .

$y = \frac{10}{3} + \frac{3 (- 5 x)}{3 (2)}$

Step 2.3.1.2.2.2

Cancel the common factor.

$y = \frac{10}{3} + \frac{3 (- 5 x)}{3 \cdot 2}$

Step 2.3.1.2.2.3

Rewrite the expression.

$y = \frac{10}{3} + \frac{- 5 x}{2}$

Step 2.3.1.3

Move the negative in front of the fraction.

$y = \frac{10}{3} - \frac{5 x}{2}$