Basic Math Examples

$0.15 (40) + 0.6 y = 0.4 (40 + y)$

Step 1

Multiply

$0.15$ by

$40$ .

$6 + 0.6 y = 0.4 (40 + y)$

Step 2

Simplify

$0.4 (40 + y)$ .

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Step 2.1

Apply the distributive property.

$6 + 0.6 y = 0.4 \cdot 40 + 0.4 y$

Step 2.2

Multiply

$0.4$ by

$40$ .

$6 + 0.6 y = 16 + 0.4 y$

$6 + 0.6 y = 16 + 0.4 y$

Step 3

Move all terms containing

$y$ to the left side of the equation.

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Step 3.1

Subtract

$0.4 y$ from both sides of the equation.

$6 + 0.6 y - 0.4 y = 16$

Step 3.2

Subtract

$0.4 y$ from

$0.6 y$ .

$6 + 0.2 y = 16$

$6 + 0.2 y = 16$

Step 4

Move all terms not containing

$y$ to the right side of the equation.

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Step 4.1

Subtract

$6$ from both sides of the equation.

$0.2 y = 16 - 6$

Step 4.2

Subtract

$6$ from

$16$ .

$0.2 y = 10$

$0.2 y = 10$

Step 5

Divide each term in

$0.2 y = 10$ by

$0.2$ and simplify.

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Step 5.1

Divide each term in

$0.2 y = 10$ by

$0.2$ .

$\frac{0.2 y}{0.2} = \frac{10}{0.2}$

Step 5.2

Simplify the left side.

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Step 5.2.1

Cancel the common factor of

$0.2$ .

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Step 5.2.1.1

Cancel the common factor.

$\frac{0.2 y}{0.2} = \frac{10}{0.2}$

Step 5.2.1.2

Divide

$y$ by

$1$ .

$y = \frac{10}{0.2}$

$y = \frac{10}{0.2}$

$y = \frac{10}{0.2}$

Step 5.3

Simplify the right side.

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Step 5.3.1

Divide

$10$ by

$0.2$ .

$y = 50$

$y = 50$

$y = 50$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$