Basic Math Examples

10 = - y + 5

$10 = - y + 5$

Step 1

Rewrite the equation as

- y + 5 = 10

$- y + 5 = 10$ .

- y + 5 = 10

$- y + 5 = 10$

Step 2

Move all terms not containing

y

$y$ to the right side of the equation.

Tap for more steps...

Step 2.1

Subtract

5

$5$ from both sides of the equation.

- y = 10 - 5

$- y = 10 - 5$

Step 2.2

Subtract

5

$5$ from

10

$10$ .

- y = 5

$- y = 5$

- y = 5

$- y = 5$

Step 3

Divide each term in

- y = 5

$- y = 5$ by

- 1

$- 1$ and simplify.

Tap for more steps...

Step 3.1

Divide each term in

- y = 5

$- y = 5$ by

- 1

$- 1$ .

\frac{- y}{- 1} = \frac{5}{- 1}

$\frac{- y}{- 1} = \frac{5}{- 1}$

Step 3.2

Simplify the left side.

Tap for more steps...

Step 3.2.1

Dividing two negative values results in a positive value.

\frac{y}{1} = \frac{5}{- 1}

$\frac{y}{1} = \frac{5}{- 1}$

Step 3.2.2

Divide

y

$y$ by

1

$1$ .

y = \frac{5}{- 1}

$y = \frac{5}{- 1}$

y = \frac{5}{- 1}

$y = \frac{5}{- 1}$

Step 3.3

Simplify the right side.

Tap for more steps...

Step 3.3.1

Divide

5

$5$ by

- 1

$- 1$ .

y = - 5

$y = - 5$

y = - 5

$y = - 5$

y = - 5

$y = - 5$

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$