Basic Math Examples

$\frac{\log (2)}{\log (1.00925)} = A$

Step 1

Rewrite the equation as $A = \frac{\log (2)}{\log (1.00925)}$ .

$A = \frac{\log (2)}{\log (1.00925)}$

Step 2

Simplify $\frac{\log (2)}{\log (1.00925)}$ .

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Step 2.1

Log base $10$ of $1.00925$ is approximately $0.00399875$ .

$A = \frac{\log (2)}{0.00399875}$

Step 2.2

Log base $10$ of $2$ is approximately $0.30102999$ .

$A = \frac{0.30102999}{0.00399875}$

Step 2.3

Divide $0.30102999$ by $0.00399875$ .

$A = 75.28087207$