Basic Math Examples

$20 = \frac{60}{100} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63$

Step 1

Rewrite the equation as $\frac{60}{100} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63 = 20$ .

$\frac{60}{100} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63 = 20$

Step 2

Simplify $\frac{60}{100} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63$ .

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Step 2.1

Cancel the common factor of $60$ and $100$ .

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Step 2.1.1

Factor $20$ out of $60$ .

$\frac{20 (3)}{100} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63 = 20$

Step 2.1.2

Cancel the common factors.

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Step 2.1.2.1

Factor $20$ out of $100$ .

$\frac{20 \cdot 3}{20 \cdot 5} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63 = 20$

Step 2.1.2.2

Cancel the common factor.

$\frac{20 \cdot 3}{20 \cdot 5} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63 = 20$

Step 2.1.2.3

Rewrite the expression.

$\frac{3}{5} \cdot (\frac{1}{2} + \frac{1}{N}) \cdot 63 = 20$

Step 2.2

Apply the distributive property.

$(\frac{3}{5} \cdot \frac{1}{2} + \frac{3}{5} \cdot \frac{1}{N}) \cdot 63 = 20$

Step 2.3

Multiply $\frac{3}{5} \cdot \frac{1}{2}$ .

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Step 2.3.1

Multiply $\frac{3}{5}$ by $\frac{1}{2}$ .

$(\frac{3}{5 \cdot 2} + \frac{3}{5} \cdot \frac{1}{N}) \cdot 63 = 20$

Step 2.3.2

Multiply $5$ by $2$ .

$(\frac{3}{10} + \frac{3}{5} \cdot \frac{1}{N}) \cdot 63 = 20$

Step 2.4

Multiply $\frac{3}{5}$ by $\frac{1}{N}$ .

$(\frac{3}{10} + \frac{3}{5 N}) \cdot 63 = 20$

Step 2.5

Apply the distributive property.

$\frac{3}{10} \cdot 63 + \frac{3}{5 N} \cdot 63 = 20$

Step 2.6

Multiply $\frac{3}{10} \cdot 63$ .

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Step 2.6.1

Combine $\frac{3}{10}$ and $63$ .

$\frac{3 \cdot 63}{10} + \frac{3}{5 N} \cdot 63 = 20$

Step 2.6.2

Multiply $3$ by $63$ .

$\frac{189}{10} + \frac{3}{5 N} \cdot 63 = 20$

Step 2.7

Multiply $\frac{3}{5 N} \cdot 63$ .

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Step 2.7.1

Combine $\frac{3}{5 N}$ and $63$ .

$\frac{189}{10} + \frac{3 \cdot 63}{5 N} = 20$

Step 2.7.2

Multiply $3$ by $63$ .

$\frac{189}{10} + \frac{189}{5 N} = 20$

Step 3

Move all terms not containing $N$ to the right side of the equation.

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Step 3.1

Subtract $\frac{189}{10}$ from both sides of the equation.

$\frac{189}{5 N} = 20 - \frac{189}{10}$

Step 3.2

To write $20$ as a fraction with a common denominator, multiply by $\frac{10}{10}$ .

$\frac{189}{5 N} = 20 \cdot \frac{10}{10} - \frac{189}{10}$

Step 3.3

Combine $20$ and $\frac{10}{10}$ .

$\frac{189}{5 N} = \frac{20 \cdot 10}{10} - \frac{189}{10}$

Step 3.4

Combine the numerators over the common denominator.

$\frac{189}{5 N} = \frac{20 \cdot 10 - 189}{10}$

Step 3.5

Simplify the numerator.

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Step 3.5.1

Multiply $20$ by $10$ .

$\frac{189}{5 N} = \frac{200 - 189}{10}$

Step 3.5.2

Subtract $189$ from $200$ .

$\frac{189}{5 N} = \frac{11}{10}$

Step 4

Find the LCD of the terms in the equation.

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Step 4.1

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$5 N, 10$

Step 4.2

Since $5 N, 10$ contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $5, 10$ then find LCM for the variable part $N^{1}$ .

Step 4.3

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

Step 4.4

Since $5$ has no factors besides $1$ and $5$ .

$5$ is a prime number

Step 4.5

$10$ has factors of $2$ and $5$ .

$2 \cdot 5$

Step 4.6

Multiply $2$ by $5$ .

$10$

Step 4.7

The factor for $N^{1}$ is $N$ itself.

$N^{1} = N$

$N$ occurs $1$ time.

Step 4.8

The LCM of $N^{1}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$N$

Step 4.9

The LCM for $5 N, 10$ is the numeric part $10$ multiplied by the variable part.

$10 N$

Step 5

Multiply each term in $\frac{189}{5 N} = \frac{11}{10}$ by $10 N$ to eliminate the fractions.

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Step 5.1

Multiply each term in $\frac{189}{5 N} = \frac{11}{10}$ by $10 N$ .

$\frac{189}{5 N} (10 N) = \frac{11}{10} (10 N)$

Step 5.2

Simplify the left side.

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Step 5.2.1

Rewrite using the commutative property of multiplication.

$10 \frac{189}{5 N} N = \frac{11}{10} (10 N)$

Step 5.2.2

Cancel the common factor of $5$ .

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Step 5.2.2.1

Factor $5$ out of $10$ .

$5 (2) \frac{189}{5 N} N = \frac{11}{10} (10 N)$

Step 5.2.2.2

Factor $5$ out of $5 N$ .

$5 (2) \frac{189}{5 (N)} N = \frac{11}{10} (10 N)$

Step 5.2.2.3

Cancel the common factor.

$5 \cdot 2 \frac{189}{5 N} N = \frac{11}{10} (10 N)$

Step 5.2.2.4

Rewrite the expression.

$2 \frac{189}{N} N = \frac{11}{10} (10 N)$

Step 5.2.3

Combine $2$ and $\frac{189}{N}$ .

$\frac{2 \cdot 189}{N} N = \frac{11}{10} (10 N)$

Step 5.2.4

Multiply $2$ by $189$ .

$\frac{378}{N} N = \frac{11}{10} (10 N)$

Step 5.2.5

Cancel the common factor of $N$ .

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Step 5.2.5.1

Cancel the common factor.

$\frac{378}{N} N = \frac{11}{10} (10 N)$

Step 5.2.5.2

Rewrite the expression.

$378 = \frac{11}{10} (10 N)$

Step 5.3

Simplify the right side.

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Step 5.3.1

Cancel the common factor of $10$ .

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Step 5.3.1.1

Factor $10$ out of $10 N$ .

$378 = \frac{11}{10} (10 (N))$

Step 5.3.1.2

Cancel the common factor.

$378 = \frac{11}{10} (10 N)$

Step 5.3.1.3

Rewrite the expression.

$378 = 11 N$

Step 6

Solve the equation.

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Step 6.1

Rewrite the equation as $11 N = 378$ .

$11 N = 378$

Step 6.2

Divide each term in $11 N = 378$ by $11$ and simplify.

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Step 6.2.1

Divide each term in $11 N = 378$ by $11$ .

$\frac{11 N}{11} = \frac{378}{11}$

Step 6.2.2

Simplify the left side.

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Step 6.2.2.1

Cancel the common factor of $11$ .

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Step 6.2.2.1.1

Cancel the common factor.

$\frac{11 N}{11} = \frac{378}{11}$

Step 6.2.2.1.2

Divide $N$ by $1$ .

$N = \frac{378}{11}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$N = \frac{378}{11}$

Decimal Form:

$N = 34.\overline{36}$

Mixed Number Form:

$N = 34 \frac{4}{11}$