Basic Math Examples

$20 (n + 7) = 4 (35 + 5 n)$

Step 1

Simplify $20 (n + 7)$ .

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Step 1.1

Rewrite.

$0 + 0 + 20 (n + 7) = 4 (35 + 5 n)$

Step 1.2

Simplify by adding zeros.

$20 (n + 7) = 4 (35 + 5 n)$

Step 1.3

Apply the distributive property.

$20 n + 20 \cdot 7 = 4 (35 + 5 n)$

Step 1.4

Multiply $20$ by $7$ .

$20 n + 140 = 4 (35 + 5 n)$

Step 2

Simplify $4 (35 + 5 n)$ .

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Step 2.1

Apply the distributive property.

$20 n + 140 = 4 \cdot 35 + 4 (5 n)$

Step 2.2

Multiply.

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Step 2.2.1

Multiply $4$ by $35$ .

$20 n + 140 = 140 + 4 (5 n)$

Step 2.2.2

Multiply $5$ by $4$ .

$20 n + 140 = 140 + 20 n$

Step 3

Move all terms containing $n$ to the left side of the equation.

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Step 3.1

Subtract $20 n$ from both sides of the equation.

$20 n + 140 - 20 n = 140$

Step 3.2

Combine the opposite terms in $20 n + 140 - 20 n$ .

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Step 3.2.1

Subtract $20 n$ from $20 n$ .

$0 + 140 = 140$

Step 3.2.2

Add $0$ and $140$ .

$140 = 140$

Step 4

Since $140 = 140$ , the equation will always be true for any value of $n$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$