Basic Math Examples

$A = b (h^{2} + 3 h + 4) - b h (h + 3) - (2 h - 15)$

Step 1

Simplify each term.

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Step 1.1

Apply the distributive property.

$A = b h^{2} + b (3 h) + b \cdot 4 - b h (h + 3) - (2 h - 15)$

Step 1.2

Simplify.

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Step 1.2.1

Rewrite using the commutative property of multiplication.

$A = b h^{2} + 3 b h + b \cdot 4 - b h (h + 3) - (2 h - 15)$

Step 1.2.2

Move $4$ to the left of $b$ .

$A = b h^{2} + 3 b h + 4 \cdot b - b h (h + 3) - (2 h - 15)$

Step 1.3

Apply the distributive property.

$A = b h^{2} + 3 b h + 4 b - b h \cdot h - b h \cdot 3 - (2 h - 15)$

Step 1.4

Multiply $h$ by $h$ by adding the exponents.

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Step 1.4.1

Move $h$ .

$A = b h^{2} + 3 b h + 4 b - b (h \cdot h) - b h \cdot 3 - (2 h - 15)$

Step 1.4.2

Multiply $h$ by $h$ .

$A = b h^{2} + 3 b h + 4 b - b h^{2} - b h \cdot 3 - (2 h - 15)$

Step 1.5

Multiply $3$ by $- 1$ .

$A = b h^{2} + 3 b h + 4 b - b h^{2} - 3 b h - (2 h - 15)$

Step 1.6

Apply the distributive property.

$A = b h^{2} + 3 b h + 4 b - b h^{2} - 3 b h - (2 h) - - 15$

Step 1.7

Multiply $2$ by $- 1$ .

$A = b h^{2} + 3 b h + 4 b - b h^{2} - 3 b h - 2 h - - 15$

Step 1.8

Multiply $- 1$ by $- 15$ .

$A = b h^{2} + 3 b h + 4 b - b h^{2} - 3 b h - 2 h + 15$

Step 2

Combine the opposite terms in $b h^{2} + 3 b h + 4 b - b h^{2} - 3 b h - 2 h + 15$ .

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Step 2.1

Subtract $b h^{2}$ from $b h^{2}$ .

$A = 3 b h + 4 b + 0 - 3 b h - 2 h + 15$

Step 2.2

Add $3 b h + 4 b$ and $0$ .

$A = 3 b h + 4 b - 3 b h - 2 h + 15$

Step 2.3

Subtract $3 b h$ from $3 b h$ .

$A = 4 b + 0 - 2 h + 15$

Step 2.4

Add $4 b$ and $0$ .

$A = 4 b - 2 h + 15$