Basic Math Examples

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\begin{matrix} h = & 9 r = & 8 \end{matrix}

$\begin{array}{r} h = & 9 \\ r = & 8 \end{array}$

Step 1

The surface area of a cone is equal to the area of the base plus the area of the cone.

$(π \cdot (r a d i u s)) \cdot ((r a d i u s) + \sqrt{{(r a d i u s)}^{2} + {(h e i g h t)}^{2}})$

Step 2

Substitute the values of the length

$r = 8$ and height

$h = 9$ into the formula. Pi

$π$ is approximately equal to

$3.14$ .

$(π \cdot 8) (8 + \sqrt{{(8)}^{2} + {(9)}^{2}})$

Step 3

Move

$8$ to the left of

$π$ .

$8 \cdot π (8 + \sqrt{{(8)}^{2} + {(9)}^{2}})$

Step 4

Simplify each term.

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Step 4.1

Raise

$8$ to the power of

$2$ .

$8 π (8 + \sqrt{64 + {(9)}^{2}})$

Step 4.2

Raise

$9$ to the power of

$2$ .

$8 π (8 + \sqrt{64 + 81})$

Step 4.3

Add

$64$ and

$81$ .

$8 π (8 + \sqrt{145})$

Step 5

Simplify by multiplying through.

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Step 5.1

Apply the distributive property.

$8 π \cdot 8 + 8 π \sqrt{145}$

Step 5.2

Multiply

$8$ by

$8$ .

$64 π + 8 π \sqrt{145}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$64 π + 8 π \sqrt{145}$

Decimal Form:

$503.70021035 \dots$