Basic Math Examples

$12 = - 4 (- 6 g - 3)$

Step 1

Rewrite the equation as $- 4 (- 6 g - 3) = 12$ .

$- 4 (- 6 g - 3) = 12$

Step 2

Divide each term in $- 4 (- 6 g - 3) = 12$ by $- 4$ and simplify.

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Step 2.1

Divide each term in $- 4 (- 6 g - 3) = 12$ by $- 4$ .

$\frac{- 4 (- 6 g - 3)}{- 4} = \frac{12}{- 4}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $- 4$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{- 4 (- 6 g - 3)}{- 4} = \frac{12}{- 4}$

Step 2.2.1.2

Divide $- 6 g - 3$ by $1$ .

$- 6 g - 3 = \frac{12}{- 4}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Divide $12$ by $- 4$ .

$- 6 g - 3 = - 3$

Step 3

Move all terms not containing $g$ to the right side of the equation.

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Step 3.1

Add $3$ to both sides of the equation.

$- 6 g = - 3 + 3$

Step 3.2

Add $- 3$ and $3$ .

$- 6 g = 0$

Step 4

Divide each term in $- 6 g = 0$ by $- 6$ and simplify.

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Step 4.1

Divide each term in $- 6 g = 0$ by $- 6$ .

$\frac{- 6 g}{- 6} = \frac{0}{- 6}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $- 6$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{- 6 g}{- 6} = \frac{0}{- 6}$

Step 4.2.1.2

Divide $g$ by $1$ .

$g = \frac{0}{- 6}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $0$ by $- 6$ .

$g = 0$