Basic Math Examples

$12 F \ln (n Z) = C$

Step 1

Divide each term in $12 F \ln (n Z) = C$ by $12 \ln (n Z)$ .

$\frac{12 F \ln (n Z)}{12 \ln (n Z)} = \frac{C}{12 \ln (n Z)}$

Step 2

Simplify the left side.

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Step 2.1

Cancel the common factor of $12$ .

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Step 2.1.1

Cancel the common factor.

$\frac{12 F \ln (n Z)}{12 \ln (n Z)} = \frac{C}{12 \ln (n Z)}$

Step 2.1.2

Rewrite the expression.

$\frac{F \ln (n Z)}{\ln (n Z)} = \frac{C}{12 \ln (n Z)}$

Step 2.2

Cancel the common factor of $\ln (n Z)$ .

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Step 2.2.1

Cancel the common factor.

$\frac{F \ln (n Z)}{\ln (n Z)} = \frac{C}{12 \ln (n Z)}$

Step 2.2.2

Divide $F$ by $1$ .

$F = \frac{C}{12 \ln (n Z)}$

Step 3

Simplify the right side.

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Step 3.1

Simplify $12 \ln (n Z)$ by moving $12$ inside the logarithm.

$F = \frac{C}{\ln ({(n Z)}^{12})}$

Step 3.2

Apply the product rule to $n Z$ .

$F = \frac{C}{\ln (n^{12} Z^{12})}$