Basic Math Examples

$| - 14 \cdot - 6 - 76 | + 8 \div 2 {(- 8 + \sqrt{36})}^{3}$

Step 1

Simplify each term.

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Step 1.1

Multiply $- 14$ by $- 6$ .

$| 84 - 76 | + 8 \div 2 {(- 8 + \sqrt{36})}^{3}$

Step 1.2

Subtract $76$ from $84$ .

$| 8 | + 8 \div 2 {(- 8 + \sqrt{36})}^{3}$

Step 1.3

The absolute value is the distance between a number and zero. The distance between $0$ and $8$ is $8$ .

$8 + 8 \div 2 {(- 8 + \sqrt{36})}^{3}$

Step 1.4

Divide $8$ by $2$ .

$8 + 4 {(- 8 + \sqrt{36})}^{3}$

Step 1.5

Simplify each term.

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Step 1.5.1

Rewrite $36$ as $6^{2}$ .

$8 + 4 {(- 8 + \sqrt{6^{2}})}^{3}$

Step 1.5.2

Pull terms out from under the radical, assuming positive real numbers.

$8 + 4 {(- 8 + 6)}^{3}$

Step 1.6

Add $- 8$ and $6$ .

$8 + 4 {(- 2)}^{3}$

Step 1.7

Raise $- 2$ to the power of $3$ .

$8 + 4 \cdot - 8$

Step 1.8

Multiply $4$ by $- 8$ .

$8 - 32$

Step 2

Subtract $32$ from $8$ .

$- 24$