Basic Math Examples

${(\sqrt{49})}^{0} - {(\sqrt{64})}^{2} + 50 \div 8^{0}$

Step 1

Find the common denominator.

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Step 1.1

Anything raised to $0$ is $1$ .

${(\sqrt{49})}^{0} - {(\sqrt{64})}^{2} + 50 \div 1$

Step 1.2

Write ${(\sqrt{49})}^{0}$ as a fraction with denominator $1$ .

$\frac{{(\sqrt{49})}^{0}}{1} - {(\sqrt{64})}^{2} + 50 \div 1$

Step 1.3

Multiply $\frac{{(\sqrt{49})}^{0}}{1}$ by $\frac{1}{1}$ .

$\frac{{(\sqrt{49})}^{0}}{1} \cdot \frac{1}{1} - {(\sqrt{64})}^{2} + 50 \div 1$

Step 1.4

Multiply $\frac{{(\sqrt{49})}^{0}}{1}$ by $\frac{1}{1}$ .

$\frac{{(\sqrt{49})}^{0}}{1} - {(\sqrt{64})}^{2} + 50 \div 1$

Step 1.5

Write $- {(\sqrt{64})}^{2}$ as a fraction with denominator $1$ .

$\frac{{(\sqrt{49})}^{0}}{1} + \frac{- {(\sqrt{64})}^{2}}{1} + 50 \div 1$

Step 1.6

Multiply $\frac{- {(\sqrt{64})}^{2}}{1}$ by $\frac{1}{1}$ .

$\frac{{(\sqrt{49})}^{0}}{1} + \frac{- {(\sqrt{64})}^{2}}{1} \cdot \frac{1}{1} + 50 \div 1$

Step 1.7

Multiply $\frac{- {(\sqrt{64})}^{2}}{1}$ by $\frac{1}{1}$ .

$\frac{{(\sqrt{49})}^{0}}{1} + \frac{- {(\sqrt{64})}^{2}}{1} + 50 \div 1$

Step 2

Combine the numerators over the common denominator.

$\frac{{(\sqrt{49})}^{0} - {(\sqrt{64})}^{2} + 50}{1}$

Step 3

Simplify each term.

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Step 3.1

Rewrite $49$ as $7^{2}$ .

$\frac{{\sqrt{7^{2}}}^{0} - {(\sqrt{64})}^{2} + 50}{1}$

Step 3.2

Pull terms out from under the radical, assuming positive real numbers.

$\frac{7^{0} - {(\sqrt{64})}^{2} + 50}{1}$

Step 3.3

Anything raised to $0$ is $1$ .

$\frac{1 - {(\sqrt{64})}^{2} + 50}{1}$

Step 3.4

Rewrite $64$ as $8^{2}$ .

$\frac{1 - {\sqrt{8^{2}}}^{2} + 50}{1}$

Step 3.5

Pull terms out from under the radical, assuming positive real numbers.

$\frac{1 - 8^{2} + 50}{1}$

Step 3.6

Raise $8$ to the power of $2$ .

$\frac{1 - 1 \cdot 64 + 50}{1}$

Step 3.7

Multiply $- 1$ by $64$ .

$\frac{1 - 64 + 50}{1}$

Step 4

Simplify the expression.

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Step 4.1

Subtract $64$ from $1$ .

$\frac{- 63 + 50}{1}$

Step 4.2

Add $- 63$ and $50$ .

$\frac{- 13}{1}$

Step 4.3

Divide $- 13$ by $1$ .

$- 13$