Basic Math Examples

0.75 \cdot 16

$0.75 \cdot 16$

Step 1

Multiply using long multiplication.

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Step 1.1

Multiply

$6$ by

$5$ . Place the ones digit

$(0)$ in the result line and carry the tens digit

$(3)$ . There is one result line for each digit in

$16$ .

		$3$
	$0$	. $7$	$5$
$⨯$		$1$	$6$
			$0$

Step 1.2

Multiply

$6$ by

$7$ and add the carried

$3$ . Place the ones digit

$(5)$ in the result line and carry the tens digit

$(4)$ . There is one result line for each digit in the

$16$ .

	$4$	$3$
	$0$	. $7$	$5$
$⨯$		$1$	$6$
		$5$	$0$

Step 1.3

Multiply

$6$ by

$0$ and add the carried

$4$ . Place the result in the next column in the result line. There is one result line for each digit in

$16$ .


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$

Step 1.4

Multiply

$1$ by

$5$ . Place the result in the next column in the result line. There is one result line for each digit in

$16$ .


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
		$5$

Step 1.5

Multiply

$1$ by

$7$ . Place the result in the next column in the result line. There is one result line for each digit in

$16$ .


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
	$7$	$5$

Step 1.6

Multiply

$1$ by

$0$ . Place the result in the next column in the result line. There is one result line for each digit in

$16$ .


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
$0$	$7$	$5$

Step 1.7

Add the numbers in each column. In this case, add

$0 + 0$ , then place the

$0$ in the result line.


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
$0$	$7$	$5$
			$0$

Step 1.8

Add the numbers in each column. In this case, add

$5 + 5$ , then place the

$0$ in the result line and carry the

$1$ .


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
$0$	$7$	$5$
		$0$	$0$

Step 1.9

Add the numbers in each column. In this case, add

$4 + 7 + 1$ , then place the

$2$ in the result line and carry the

$1$ .


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
$0$	$7$	$5$
$1$	$2$	$0$	$0$


	$0$	. $7$	$5$
$⨯$		$1$	$6$
	$4$	$5$	$0$
$0$	$7$	$5$
$1$	$2$	$0$	$0$

Step 2

To find the number of decimal places needed in the answer, add the number of decimal places in the multiplier and multiplicand. In this case, there is a total of

$2$ , so the answer must have

$2$ decimal places as well.

$12$