Basic Math Examples

$0.5 {(1 + 6^{2})}^{- 0.5} (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 1

Raise $6$ to the power of $2$ .

$0.5 {(1 + 36)}^{- 0.5} (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 2

Add $1$ and $36$ .

$0.5 \cdot 37^{- 0.5} (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 3

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$0.5 \cdot \frac{1}{37^{0.5}} (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 4

Simplify the expression.

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Step 4.1

Raise $37$ to the power of $0.5$ .

$0.5 \cdot \frac{1}{6.08276253} (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 4.2

Divide $1$ by $6.08276253$ .

$0.5 \cdot 0.16439898 (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 4.3

Multiply $0.5$ by $0.16439898$ .

$0.08219949 (2 (1) \cdot 3 + 2 (6) \cdot 5)$

Step 5

Simplify each term.

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Step 5.1

Multiply $2 (1) \cdot 3$ .

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Step 5.1.1

Multiply $2$ by $1$ .

$0.08219949 (2 \cdot 3 + 2 (6) \cdot 5)$

Step 5.1.2

Multiply $2$ by $3$ .

$0.08219949 (6 + 2 (6) \cdot 5)$

Step 5.2

Multiply $2 (6) \cdot 5$ .

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Step 5.2.1

Multiply $2$ by $6$ .

$0.08219949 (6 + 12 \cdot 5)$

Step 5.2.2

Multiply $12$ by $5$ .

$0.08219949 (6 + 60)$

Step 6

Simplify the expression.

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Step 6.1

Add $6$ and $60$ .

$0.08219949 \cdot 66$

Step 6.2

Multiply $0.08219949$ by $66$ .

$5.42516658$