Basic Math Examples

$(5^{2} \cdot (3^{2} + 2^{3}) - \sqrt{36}) \cdot \sqrt[3]{64}$

Step 1

Simplify each term.

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Step 1.1

Raise $5$ to the power of $2$ .

$(25 \cdot (3^{2} + 2^{3}) - \sqrt{36}) \cdot \sqrt[3]{64}$

Step 1.2

Simplify each term.

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Step 1.2.1

Raise $3$ to the power of $2$ .

$(25 \cdot (9 + 2^{3}) - \sqrt{36}) \cdot \sqrt[3]{64}$

Step 1.2.2

Raise $2$ to the power of $3$ .

$(25 \cdot (9 + 8) - \sqrt{36}) \cdot \sqrt[3]{64}$

Step 1.3

Add $9$ and $8$ .

$(25 \cdot 17 - \sqrt{36}) \cdot \sqrt[3]{64}$

Step 1.4

Multiply $25$ by $17$ .

$(425 - \sqrt{36}) \cdot \sqrt[3]{64}$

Step 1.5

Rewrite $36$ as $6^{2}$ .

$(425 - \sqrt{6^{2}}) \cdot \sqrt[3]{64}$

Step 1.6

Pull terms out from under the radical, assuming positive real numbers.

$(425 - 1 \cdot 6) \cdot \sqrt[3]{64}$

Step 1.7

Multiply $- 1$ by $6$ .

$(425 - 6) \cdot \sqrt[3]{64}$

Step 2

Simplify the expression.

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Step 2.1

Subtract $6$ from $425$ .

$419 \cdot \sqrt[3]{64}$

Step 2.2

Rewrite $64$ as $4^{3}$ .

$419 \cdot \sqrt[3]{4^{3}}$

Step 2.3

Pull terms out from under the radical, assuming real numbers.

$419 \cdot 4$

Step 2.4

Multiply $419$ by $4$ .

$1676$