Basic Math Examples

$\frac{1000 (\frac{0.035}{240})}{(1 + {(\frac{0.035}{240})}^{240 (20)} - 1)}$

Step 1

Combine $1000$ and $\frac{0.035}{240}$ .

$\frac{\frac{1000 \cdot 0.035}{240}}{1 + {(\frac{0.035}{240})}^{240 (20)} - 1}$

Step 2

Simplify the denominator.

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Step 2.1

Divide $0.035$ by $240$ .

$\frac{\frac{1000 \cdot 0.035}{240}}{1 + {0.00014583}^{240 (20)} - 1}$

Step 2.2

Multiply $240$ by $20$ .

$\frac{\frac{1000 \cdot 0.035}{240}}{1 + {0.00014583}^{4800} - 1}$

Step 2.3

Subtract $1$ from $1$ .

$\frac{\frac{1000 \cdot 0.035}{240}}{{0.00014583}^{4800} + 0}$

Step 2.4

Add ${0.00014583}^{4800}$ and $0$ .

$\frac{\frac{1000 \cdot 0.035}{240}}{{0.00014583}^{4800}}$

Step 3

Reduce the expression by cancelling the common factors.

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Step 3.1

Multiply $1000$ by $0.035$ .

$\frac{\frac{35}{240}}{{0.00014583}^{4800}}$

Step 3.2

Cancel the common factor of $35$ and $240$ .

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Step 3.2.1

Factor $5$ out of $35$ .

$\frac{\frac{5 (7)}{240}}{{0.00014583}^{4800}}$

Step 3.2.2

Cancel the common factors.

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Step 3.2.2.1

Factor $5$ out of $240$ .

$\frac{\frac{5 \cdot 7}{5 \cdot 48}}{{0.00014583}^{4800}}$

Step 3.2.2.2

Cancel the common factor.

$\frac{\frac{5 \cdot 7}{5 \cdot 48}}{{0.00014583}^{4800}}$

Step 3.2.2.3

Rewrite the expression.

$\frac{\frac{7}{48}}{{0.00014583}^{4800}}$

Step 4

Multiply the numerator by the reciprocal of the denominator.

$\frac{7}{48} \cdot \frac{1}{{0.00014583}^{4800}}$

Step 5

Combine.

$\frac{7 \cdot 1}{48 \cdot {0.00014583}^{4800}}$

Step 6

Multiply $7$ by $1$ .

$\frac{7}{48 \cdot {0.00014583}^{4800}}$