Basic Math Examples

$\frac{4 (7 - 4) + 2}{2^{2} - 2}$

Step 1

Cancel the common factor of $4 (7 - 4) + 2$ and $2^{2} - 2$ .

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Step 1.1

Factor $- 1$ out of $2^{2}$ .

$\frac{4 (7 - 4) + 2}{- 1 (- 2^{2}) - 2}$

Step 1.2

Rewrite $- 2$ as $- 1 (2)$ .

$\frac{4 (7 - 4) + 2}{- 1 (- 2^{2}) - 1 (2)}$

Step 1.3

Factor $- 1$ out of $- 1 (- 2^{2}) - 1 (2)$ .

$\frac{4 (7 - 4) + 2}{- 1 (- 2^{2} + 2)}$

Step 1.4

Factor $2$ out of $4 (7 - 4)$ .

$\frac{2 (2 (7 - 4)) + 2}{- 1 (- 2^{2} + 2)}$

Step 1.5

Factor $2$ out of $2$ .

$\frac{2 (2 (7 - 4)) + 2 \cdot 1}{- 1 (- 2^{2} + 2)}$

Step 1.6

Factor $2$ out of $2 (2 (7 - 4)) + 2 (1)$ .

$\frac{2 (2 (7 - 4) + 1)}{- 1 (- 2^{2} + 2)}$

Step 1.7

Cancel the common factors.

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Step 1.7.1

Factor $2$ out of $- 1 (- 2^{2} + 2)$ .

$\frac{2 (2 (7 - 4) + 1)}{2 (- 1 (- 1 \cdot 2 + 1))}$

Step 1.7.2

Cancel the common factor.

$\frac{2 (2 (7 - 4) + 1)}{2 (- 1 (- 1 \cdot 2 + 1))}$

Step 1.7.3

Rewrite the expression.

$\frac{2 (7 - 4) + 1}{- 1 (- 1 \cdot 2 + 1)}$

Step 2

Simplify the numerator.

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Step 2.1

Subtract $4$ from $7$ .

$\frac{2 \cdot 3 + 1}{- 1 (- 1 \cdot 2 + 1)}$

Step 2.2

Multiply $2$ by $3$ .

$\frac{6 + 1}{- 1 (- 1 \cdot 2 + 1)}$

Step 2.3

Add $6$ and $1$ .

$\frac{7}{- 1 (- 1 \cdot 2 + 1)}$

Step 3

Simplify the denominator.

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Step 3.1

Multiply $- 1$ by $2$ .

$\frac{7}{- 1 (- 2 + 1)}$

Step 3.2

Add $- 2$ and $1$ .

$\frac{7}{- 1 \cdot - 1}$

Step 4

Simplify the expression.

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Step 4.1

Multiply $- 1$ by $- 1$ .

$\frac{7}{1}$

Step 4.2

Divide $7$ by $1$ .

$7$