Basic Math Examples

$(6.67 \cdot 10^{- 11}) \cdot {(9.11 \cdot 10^{- 31})}^{2}$

Step 1

Apply the product rule to $9.11 \cdot 10^{- 31}$ .

$6.67 \cdot 10^{- 11} \cdot ({9.11}^{2} \cdot {(10^{- 31})}^{2})$

Step 2

Raise $9.11$ to the power of $2$ .

$6.67 \cdot 10^{- 11} \cdot (82.9921 \cdot {(10^{- 31})}^{2})$

Step 3

Multiply the exponents in ${(10^{- 31})}^{2}$ .

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Step 3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$6.67 \cdot 10^{- 11} \cdot (82.9921 \cdot 10^{- 31 \cdot 2})$

Step 3.2

Multiply $- 31$ by $2$ .

$6.67 \cdot 10^{- 11} \cdot 82.9921 \cdot 10^{- 62}$

Step 4

Multiply $6.67$ by $82.9921$ .

$553.557307 (10^{- 11} \cdot 10^{- 62})$

Step 5

Multiply $10^{- 11}$ by $10^{- 62}$ by adding the exponents.

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Step 5.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$553.557307 \cdot 10^{- 11 - 62}$

Step 5.2

Subtract $62$ from $- 11$ .

$553.557307 \cdot 10^{- 73}$

Step 6

Move the decimal point in $553.557307$ to the left by $2$ places and increase the power of $10^{- 73}$ by $2$ .

$5.53557307 \cdot 10^{- 71}$