Basic Math Examples



\begin{array}{r} r = & 4 \end{array}

$\begin{array}{r} r = & 4 \end{array}$

Step 1

The volume of a sphere is equal to

\frac{4}{3}

$\frac{4}{3}$ times Pi

π

$π$ times the radius cubed.

\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}

$\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}$

Step 2

Substitute the value of the radius

r = 4

$r = 4$ into the formula to find the volume of the sphere. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

\frac{4}{3} \cdot π \cdot 4^{3}

$\frac{4}{3} \cdot π \cdot 4^{3}$

Step 3

Combine

\frac{4}{3}

$\frac{4}{3}$ and

π

$π$ .

\frac{4 π}{3} \cdot 4^{3}

$\frac{4 π}{3} \cdot 4^{3}$

Step 4

Raise

4

$4$ to the power of

3

$3$ .

\frac{4 π}{3} \cdot 64

$\frac{4 π}{3} \cdot 64$

Step 5

Multiply

\frac{4 π}{3} \cdot 64

$\frac{4 π}{3} \cdot 64$ .

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Step 5.1

Combine

\frac{4 π}{3}

$\frac{4 π}{3}$ and

64

$64$ .

\frac{4 π \cdot 64}{3}

$\frac{4 π \cdot 64}{3}$

Step 5.2

Multiply

64

$64$ by

4

$4$ .

\frac{256 π}{3}

$\frac{256 π}{3}$

\frac{256 π}{3}

$\frac{256 π}{3}$

Step 6

The result can be shown in multiple forms.

Exact Form:

\frac{256 π}{3}

$\frac{256 π}{3}$

Decimal Form:

268.08257310 \dots

$268.08257310 \dots$



\begin{array}{r} r = & 4 \end{array}

$\begin{array}{r} r = & 4 \end{array}$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$