Basic Math Examples

$24 L^{3} g - m (\frac{L \cdot 3}{1855} \cdot i n - oz)$

Step 1

Simplify each term.

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Step 1.1

Rewrite using the commutative property of multiplication.

$24 L^{3} g - m (i \frac{L \cdot 3}{1855} n - oz)$

Step 1.2

Move $3$ to the left of $L$ .

$24 L^{3} g - m (i \frac{3 \cdot L}{1855} n - oz)$

Step 1.3

Multiply $3$ by $L$ .

$24 L^{3} g - m (i \frac{3 L}{1855} n - oz)$

Step 1.4

Combine $i$ and $\frac{3 L}{1855}$ .

$24 L^{3} g - m (\frac{i (3 L)}{1855} n - oz)$

Step 1.5

Remove parentheses.

$24 L^{3} g - m (\frac{i \cdot 3 L}{1855} n - oz)$

Step 1.6

Move $3$ to the left of $i$ .

$24 L^{3} g - m (\frac{3 \cdot i L}{1855} n - oz)$

Step 1.7

Multiply $3$ by $i$ .

$24 L^{3} g - m (\frac{3 i L}{1855} n - oz)$

Step 1.8

Combine $\frac{3 i L}{1855}$ and $n$ .

$24 L^{3} g - m (\frac{3 i L n}{1855} - oz)$

Step 2

Apply the distributive property.

$24 L^{3} g - m \frac{3 i L n}{1855} - m (- oz)$

Step 3

Combine $\frac{3 i L n}{1855}$ and $m$ .

$24 L^{3} g - \frac{3 i L n m}{1855} - m (- oz)$

Step 4

Multiply $- m \cdot - oz$ .

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Step 4.1

Multiply $- 1$ by $- 1$ .

$24 L^{3} g - \frac{3 i L n m}{1855} + 1 m oz$

Step 4.2

Multiply $m$ by $1$ .

$24 L^{3} g - \frac{3 i L n m}{1855} + m oz$