Basic Math Examples

$(\frac{5 a^{2} - a}{25 a^{2} - 10 a + 1} + \frac{4}{1 - 25 a^{2}}) \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 1

To write $\frac{5 a^{2} - a}{25 a^{2} - 10 a + 1}$ as a fraction with a common denominator, multiply by $\frac{1 - 25 a^{2}}{1 - 25 a^{2}}$ .

$(\frac{5 a^{2} - a}{25 a^{2} - 10 a + 1} \cdot \frac{1 - 25 a^{2}}{1 - 25 a^{2}} + \frac{4}{1 - 25 a^{2}}) \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 2

To write $\frac{4}{1 - 25 a^{2}}$ as a fraction with a common denominator, multiply by $\frac{25 a^{2} - 10 a + 1}{25 a^{2} - 10 a + 1}$ .

$(\frac{5 a^{2} - a}{25 a^{2} - 10 a + 1} \cdot \frac{1 - 25 a^{2}}{1 - 25 a^{2}} + \frac{4}{1 - 25 a^{2}} \cdot \frac{25 a^{2} - 10 a + 1}{25 a^{2} - 10 a + 1}) \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 3

Write each expression with a common denominator of $(25 a^{2} - 10 a + 1) (1 - 25 a^{2})$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.1

Multiply $\frac{5 a^{2} - a}{25 a^{2} - 10 a + 1}$ by $\frac{1 - 25 a^{2}}{1 - 25 a^{2}}$ .

$(\frac{(5 a^{2} - a) (1 - 25 a^{2})}{(25 a^{2} - 10 a + 1) (1 - 25 a^{2})} + \frac{4}{1 - 25 a^{2}} \cdot \frac{25 a^{2} - 10 a + 1}{25 a^{2} - 10 a + 1}) \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 3.2

Multiply $\frac{4}{1 - 25 a^{2}}$ by $\frac{25 a^{2} - 10 a + 1}{25 a^{2} - 10 a + 1}$ .

$(\frac{(5 a^{2} - a) (1 - 25 a^{2})}{(25 a^{2} - 10 a + 1) (1 - 25 a^{2})} + \frac{4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)}) \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 3.3

Reorder the factors of $(25 a^{2} - 10 a + 1) (1 - 25 a^{2})$ .

$(\frac{(5 a^{2} - a) (1 - 25 a^{2})}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} + \frac{4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)}) \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 4

Combine the numerators over the common denominator.

$\frac{(5 a^{2} - a) (1 - 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \div (1 - \frac{3}{5 a - 1}) - \frac{a}{5 a + 1}$

Step 5

Simplify each term.

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Step 5.1

Rewrite the division as a fraction.

$\frac{\frac{(5 a^{2} - a) (1 - 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)}}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.2

Multiply the numerator by the reciprocal of the denominator.

$\frac{(5 a^{2} - a) (1 - 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3

Simplify the numerator.

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Step 5.3.1

Expand $(5 a^{2} - a) (1 - 25 a^{2})$ using the FOIL Method.

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Step 5.3.1.1

Apply the distributive property.

$\frac{5 a^{2} (1 - 25 a^{2}) - a (1 - 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.1.2

Apply the distributive property.

$\frac{5 a^{2} \cdot 1 + 5 a^{2} (- 25 a^{2}) - a (1 - 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.1.3

Apply the distributive property.

$\frac{5 a^{2} \cdot 1 + 5 a^{2} (- 25 a^{2}) - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2

Simplify each term.

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Step 5.3.2.1

Multiply $5$ by $1$ .

$\frac{5 a^{2} + 5 a^{2} (- 25 a^{2}) - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.2

Rewrite using the commutative property of multiplication.

$\frac{5 a^{2} + 5 \cdot - 25 a^{2} a^{2} - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.3

Multiply $a^{2}$ by $a^{2}$ by adding the exponents.

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Step 5.3.2.3.1

Move $a^{2}$ .

$\frac{5 a^{2} + 5 \cdot - 25 (a^{2} a^{2}) - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.3.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 a^{2} + 5 \cdot - 25 a^{2 + 2} - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.3.3

Add $2$ and $2$ .

$\frac{5 a^{2} + 5 \cdot - 25 a^{4} - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.4

Multiply $5$ by $- 25$ .

$\frac{5 a^{2} - 125 a^{4} - a \cdot 1 - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.5

Multiply $- 1$ by $1$ .

$\frac{5 a^{2} - 125 a^{4} - a - a (- 25 a^{2}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.6

Rewrite using the commutative property of multiplication.

$\frac{5 a^{2} - 125 a^{4} - a - 1 \cdot - 25 a \cdot a^{2} + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.7

Multiply $a$ by $a^{2}$ by adding the exponents.

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Step 5.3.2.7.1

Move $a^{2}$ .

$\frac{5 a^{2} - 125 a^{4} - a - 1 \cdot - 25 (a^{2} a) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.7.2

Multiply $a^{2}$ by $a$ .

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Step 5.3.2.7.2.1

Raise $a$ to the power of $1$ .

$\frac{5 a^{2} - 125 a^{4} - a - 1 \cdot - 25 (a^{2} a^{1}) + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.7.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 a^{2} - 125 a^{4} - a - 1 \cdot - 25 a^{2 + 1} + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.7.3

Add $2$ and $1$ .

$\frac{5 a^{2} - 125 a^{4} - a - 1 \cdot - 25 a^{3} + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.2.8

Multiply $- 1$ by $- 25$ .

$\frac{5 a^{2} - 125 a^{4} - a + 25 a^{3} + 4 (25 a^{2} - 10 a + 1)}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.3

Apply the distributive property.

$\frac{5 a^{2} - 125 a^{4} - a + 25 a^{3} + 4 (25 a^{2}) + 4 (- 10 a) + 4 \cdot 1}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.4

Simplify.

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Step 5.3.4.1

Multiply $25$ by $4$ .

$\frac{5 a^{2} - 125 a^{4} - a + 25 a^{3} + 100 a^{2} + 4 (- 10 a) + 4 \cdot 1}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.4.2

Multiply $- 10$ by $4$ .

$\frac{5 a^{2} - 125 a^{4} - a + 25 a^{3} + 100 a^{2} - 40 a + 4 \cdot 1}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.4.3

Multiply $4$ by $1$ .

$\frac{5 a^{2} - 125 a^{4} - a + 25 a^{3} + 100 a^{2} - 40 a + 4}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.5

Add $5 a^{2}$ and $100 a^{2}$ .

$\frac{- 125 a^{4} - a + 25 a^{3} + 105 a^{2} - 40 a + 4}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.3.6

Subtract $40 a$ from $- a$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4

Simplify the denominator.

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Step 5.4.1

Rewrite $1$ as $1^{2}$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1^{2} - 25 a^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.2

Rewrite $25 a^{2}$ as ${(5 a)}^{2}$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1^{2} - {(5 a)}^{2}) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = 5 a$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (1 - (5 a)) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.4

Multiply $5$ by $- 1$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (1 - 5 a) (25 a^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.5

Factor using the perfect square rule.

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Step 5.4.5.1

Rewrite $25 a^{2}$ as ${(5 a)}^{2}$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (1 - 5 a) ({(5 a)}^{2} - 10 a + 1)} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.5.2

Rewrite $1$ as $1^{2}$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (1 - 5 a) ({(5 a)}^{2} - 10 a + 1^{2})} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.5.3

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$10 a = 2 \cdot (5 a) \cdot 1$

Step 5.4.5.4

Rewrite the polynomial.

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (1 - 5 a) ({(5 a)}^{2} - 2 \cdot (5 a) \cdot 1 + 1^{2})} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.5.5

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = 5 a$ and $b = 1$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (1 - 5 a) {(5 a - 1)}^{2}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6

Combine exponents.

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Step 5.4.6.1

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (- 1 (- 1) - 5 a) {(5 a - 1)}^{2}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.2

Factor $- 1$ out of $- 5 a$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (- 1 (- 1) - (5 a)) {(5 a - 1)}^{2}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.3

Factor $- 1$ out of $- 1 (- 1) - (5 a)$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) (- 1 (- 1 + 5 a)) {(5 a - 1)}^{2}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.4

Reorder terms.

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) \cdot - 1 (5 a - 1) {(5 a - 1)}^{2}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.5

Multiply $5 a - 1$ by ${(5 a - 1)}^{2}$ by adding the exponents.

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Step 5.4.6.5.1

Move ${(5 a - 1)}^{2}$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) \cdot - 1 ({(5 a - 1)}^{2} (5 a - 1))} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.5.2

Multiply ${(5 a - 1)}^{2}$ by $5 a - 1$ .

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Step 5.4.6.5.2.1

Raise $5 a - 1$ to the power of $1$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) \cdot - 1 ({(5 a - 1)}^{2} {(5 a - 1)}^{1})} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.5.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) \cdot - 1 {(5 a - 1)}^{2 + 1}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.6.5.3

Add $2$ and $1$ .

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) \cdot - 1 {(5 a - 1)}^{3}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.4.7

Factor out negative.

$\frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{- (1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.5

Move the negative in front of the fraction.

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{1}{1 - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.6

Simplify the denominator.

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Step 5.6.1

Write $1$ as a fraction with a common denominator.

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{1}{\frac{5 a - 1}{5 a - 1} - \frac{3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.6.2

Combine the numerators over the common denominator.

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{1}{\frac{5 a - 1 - 3}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.6.3

Subtract $3$ from $- 1$ .

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{1}{\frac{5 a - 4}{5 a - 1}} - \frac{a}{5 a + 1}$

Step 5.7

Multiply the numerator by the reciprocal of the denominator.

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}} (1 \frac{5 a - 1}{5 a - 4}) - \frac{a}{5 a + 1}$

Step 5.8

Multiply $\frac{5 a - 1}{5 a - 4}$ by $1$ .

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{5 a - 1}{5 a - 4} - \frac{a}{5 a + 1}$

Step 5.9

Cancel the common factor of $5 a - 1$ .

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Step 5.9.1

Move the leading negative in $- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{3}}$ into the numerator.

$\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4)}{(1 + 5 a) {(5 a - 1)}^{3}} \cdot \frac{5 a - 1}{5 a - 4} - \frac{a}{5 a + 1}$

Step 5.9.2

Factor $5 a - 1$ out of $(1 + 5 a) {(5 a - 1)}^{3}$ .

$\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4)}{(5 a - 1) ((1 + 5 a) {(5 a - 1)}^{2})} \cdot \frac{5 a - 1}{5 a - 4} - \frac{a}{5 a + 1}$

Step 5.9.3

Cancel the common factor.

$\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4)}{(5 a - 1) ((1 + 5 a) {(5 a - 1)}^{2})} \cdot \frac{5 a - 1}{5 a - 4} - \frac{a}{5 a + 1}$

Step 5.9.4

Rewrite the expression.

$\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4)}{(1 + 5 a) {(5 a - 1)}^{2}} \cdot \frac{1}{5 a - 4} - \frac{a}{5 a + 1}$

Step 5.10

Multiply $\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4)}{(1 + 5 a) {(5 a - 1)}^{2}}$ by $\frac{1}{5 a - 4}$ .

$\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4)}{(1 + 5 a) {(5 a - 1)}^{2} (5 a - 4)} - \frac{a}{5 a + 1}$

Step 5.11

Move the negative in front of the fraction.

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(1 + 5 a) {(5 a - 1)}^{2} (5 a - 4)} - \frac{a}{5 a + 1}$

Step 6

Reorder terms.

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(5 a + 1) {(5 a - 1)}^{2} (5 a - 4)} - \frac{a}{5 a + 1}$

Step 7

To write $- \frac{a}{5 a + 1}$ as a fraction with a common denominator, multiply by $\frac{(5 a - 4) {(5 a - 1)}^{2}}{(5 a - 4) {(5 a - 1)}^{2}}$ .

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(5 a + 1) {(5 a - 1)}^{2} (5 a - 4)} - \frac{a}{5 a + 1} \cdot \frac{(5 a - 4) {(5 a - 1)}^{2}}{(5 a - 4) {(5 a - 1)}^{2}}$

Step 8

Write each expression with a common denominator of $(5 a + 1) (5 a - 4) {(5 a - 1)}^{2}$ , by multiplying each by an appropriate factor of $1$ .

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Step 8.1

Multiply $\frac{a}{5 a + 1}$ by $\frac{(5 a - 4) {(5 a - 1)}^{2}}{(5 a - 4) {(5 a - 1)}^{2}}$ .

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{(5 a + 1) {(5 a - 1)}^{2} (5 a - 4)} - \frac{a ((5 a - 4) {(5 a - 1)}^{2})}{(5 a + 1) ((5 a - 4) {(5 a - 1)}^{2})}$

Step 8.2

Reorder the factors of $(5 a + 1) {(5 a - 1)}^{2} (5 a - 4)$ .

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)} - \frac{a ((5 a - 4) {(5 a - 1)}^{2})}{(5 a + 1) ((5 a - 4) {(5 a - 1)}^{2})}$

Step 8.3

Reorder the factors of $(5 a + 1) ((5 a - 4) {(5 a - 1)}^{2})$ .

$- \frac{- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)} - \frac{a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 9

Combine the numerators over the common denominator.

$\frac{- (- 125 a^{4} + 25 a^{3} + 105 a^{2} - 41 a + 4) - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10

Simplify the numerator.

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Step 10.1

Apply the distributive property.

$\frac{- (- 125 a^{4}) - (25 a^{3}) - (105 a^{2}) - (- 41 a) - 1 \cdot 4 - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.2

Simplify.

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Step 10.2.1

Multiply $- 125$ by $- 1$ .

$\frac{125 a^{4} - (25 a^{3}) - (105 a^{2}) - (- 41 a) - 1 \cdot 4 - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.2.2

Multiply $25$ by $- 1$ .

$\frac{125 a^{4} - 25 a^{3} - (105 a^{2}) - (- 41 a) - 1 \cdot 4 - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.2.3

Multiply $105$ by $- 1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} - (- 41 a) - 1 \cdot 4 - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.2.4

Multiply $- 41$ by $- 1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 1 \cdot 4 - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.2.5

Multiply $- 1$ by $4$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) {(5 a - 1)}^{2})}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.3

Rewrite ${(5 a - 1)}^{2}$ as $(5 a - 1) (5 a - 1)$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) ((5 a - 1) (5 a - 1)))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.4

Expand $(5 a - 1) (5 a - 1)$ using the FOIL Method.

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Step 10.4.1

Apply the distributive property.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (5 a (5 a - 1) - 1 (5 a - 1)))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.4.2

Apply the distributive property.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (5 a (5 a) + 5 a \cdot - 1 - 1 (5 a - 1)))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.4.3

Apply the distributive property.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (5 a (5 a) + 5 a \cdot - 1 - 1 (5 a) - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5

Simplify and combine like terms.

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Step 10.5.1

Simplify each term.

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Step 10.5.1.1

Rewrite using the commutative property of multiplication.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (5 \cdot 5 a \cdot a + 5 a \cdot - 1 - 1 (5 a) - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.1.2

Multiply $a$ by $a$ by adding the exponents.

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Step 10.5.1.2.1

Move $a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (5 \cdot 5 (a \cdot a) + 5 a \cdot - 1 - 1 (5 a) - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.1.2.2

Multiply $a$ by $a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (5 \cdot 5 a^{2} + 5 a \cdot - 1 - 1 (5 a) - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.1.3

Multiply $5$ by $5$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (25 a^{2} + 5 a \cdot - 1 - 1 (5 a) - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.1.4

Multiply $- 1$ by $5$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (25 a^{2} - 5 a - 1 (5 a) - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.1.5

Multiply $5$ by $- 1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (25 a^{2} - 5 a - 5 a - 1 \cdot - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.1.6

Multiply $- 1$ by $- 1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (25 a^{2} - 5 a - 5 a + 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.5.2

Subtract $5 a$ from $- 5 a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a ((5 a - 4) (25 a^{2} - 10 a + 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.6

Expand $(5 a - 4) (25 a^{2} - 10 a + 1)$ by multiplying each term in the first expression by each term in the second expression.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (5 a (25 a^{2}) + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7

Simplify each term.

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Step 10.7.1

Rewrite using the commutative property of multiplication.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (5 \cdot 25 a \cdot a^{2} + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.2

Multiply $a$ by $a^{2}$ by adding the exponents.

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Step 10.7.2.1

Move $a^{2}$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (5 \cdot 25 (a^{2} a) + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.2.2

Multiply $a^{2}$ by $a$ .

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Step 10.7.2.2.1

Raise $a$ to the power of $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (5 \cdot 25 (a^{2} a^{1}) + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (5 \cdot 25 a^{2 + 1} + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.2.3

Add $2$ and $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (5 \cdot 25 a^{3} + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.3

Multiply $5$ by $25$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} + 5 a (- 10 a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.4

Rewrite using the commutative property of multiplication.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} + 5 \cdot - 10 a \cdot a + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.5

Multiply $a$ by $a$ by adding the exponents.

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Step 10.7.5.1

Move $a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} + 5 \cdot - 10 (a \cdot a) + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.5.2

Multiply $a$ by $a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} + 5 \cdot - 10 a^{2} + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.6

Multiply $5$ by $- 10$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 50 a^{2} + 5 a \cdot 1 - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.7

Multiply $5$ by $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 50 a^{2} + 5 a - 4 (25 a^{2}) - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.8

Multiply $25$ by $- 4$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 50 a^{2} + 5 a - 100 a^{2} - 4 (- 10 a) - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.9

Multiply $- 10$ by $- 4$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 50 a^{2} + 5 a - 100 a^{2} + 40 a - 4 \cdot 1)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.7.10

Multiply $- 4$ by $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 50 a^{2} + 5 a - 100 a^{2} + 40 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.8

Subtract $100 a^{2}$ from $- 50 a^{2}$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 150 a^{2} + 5 a + 40 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.9

Add $5 a$ and $40 a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3} - 150 a^{2} + 45 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.10

Apply the distributive property.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - a (125 a^{3}) - a (- 150 a^{2}) - a (45 a) - a \cdot - 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.11

Simplify.

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Step 10.11.1

Rewrite using the commutative property of multiplication.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 a \cdot a^{3} - a (- 150 a^{2}) - a (45 a) - a \cdot - 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.11.2

Rewrite using the commutative property of multiplication.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 a \cdot a^{3} - 1 \cdot - 150 a \cdot a^{2} - a (45 a) - a \cdot - 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.11.3

Rewrite using the commutative property of multiplication.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 a \cdot a^{3} - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a - a \cdot - 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.11.4

Multiply $- 4$ by $- 1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 a \cdot a^{3} - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12

Simplify each term.

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Step 10.12.1

Multiply $a$ by $a^{3}$ by adding the exponents.

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Step 10.12.1.1

Move $a^{3}$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 (a^{3} a) - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.1.2

Multiply $a^{3}$ by $a$ .

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Step 10.12.1.2.1

Raise $a$ to the power of $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 (a^{3} a^{1}) - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 a^{3 + 1} - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.1.3

Add $3$ and $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 1 \cdot 125 a^{4} - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.2

Multiply $- 1$ by $125$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} - 1 \cdot - 150 a \cdot a^{2} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.3

Multiply $a$ by $a^{2}$ by adding the exponents.

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Step 10.12.3.1

Move $a^{2}$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} - 1 \cdot - 150 (a^{2} a) - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.3.2

Multiply $a^{2}$ by $a$ .

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Step 10.12.3.2.1

Raise $a$ to the power of $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} - 1 \cdot - 150 (a^{2} a^{1}) - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.3.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} - 1 \cdot - 150 a^{2 + 1} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.3.3

Add $2$ and $1$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} - 1 \cdot - 150 a^{3} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.4

Multiply $- 1$ by $- 150$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} + 150 a^{3} - 1 \cdot 45 a \cdot a + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.5

Multiply $a$ by $a$ by adding the exponents.

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Step 10.12.5.1

Move $a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} + 150 a^{3} - 1 \cdot 45 (a \cdot a) + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.5.2

Multiply $a$ by $a$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} + 150 a^{3} - 1 \cdot 45 a^{2} + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.12.6

Multiply $- 1$ by $45$ .

$\frac{125 a^{4} - 25 a^{3} - 105 a^{2} + 41 a - 4 - 125 a^{4} + 150 a^{3} - 45 a^{2} + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.13

Subtract $125 a^{4}$ from $125 a^{4}$ .

$\frac{- 25 a^{3} - 105 a^{2} + 41 a - 4 + 0 + 150 a^{3} - 45 a^{2} + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.14

Add $- 25 a^{3}$ and $0$ .

$\frac{- 25 a^{3} - 105 a^{2} + 41 a - 4 + 150 a^{3} - 45 a^{2} + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.15

Add $- 25 a^{3}$ and $150 a^{3}$ .

$\frac{125 a^{3} - 105 a^{2} + 41 a - 4 - 45 a^{2} + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.16

Subtract $45 a^{2}$ from $- 105 a^{2}$ .

$\frac{125 a^{3} - 150 a^{2} + 41 a - 4 + 4 a}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.17

Add $41 a$ and $4 a$ .

$\frac{125 a^{3} - 150 a^{2} + 45 a - 4}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18

Rewrite $125 a^{3} - 150 a^{2} + 45 a - 4$ in a factored form.

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Step 10.18.1

Factor $125 a^{3} - 150 a^{2} + 45 a - 4$ using the rational roots test.

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Step 10.18.1.1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 4, \pm 2$

$q = \pm 1, \pm 125, \pm 5, \pm 25$

Step 10.18.1.2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm 0.008, \pm 0.2, \pm 0.04, \pm 4, \pm 0.032, \pm 0.8, \pm 0.16, \pm 2, \pm 0.016, \pm 0.4, \pm 0.08$

Step 10.18.1.3

Substitute $0.2$ and simplify the expression. In this case, the expression is equal to $0$ so $0.2$ is a root of the polynomial.

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Step 10.18.1.3.1

Substitute $0.2$ into the polynomial.

$125 \cdot {0.2}^{3} - 150 \cdot {0.2}^{2} + 45 \cdot 0.2 - 4$

Step 10.18.1.3.2

Raise $0.2$ to the power of $3$ .

$125 \cdot 0.008 - 150 \cdot {0.2}^{2} + 45 \cdot 0.2 - 4$

Step 10.18.1.3.3

Multiply $125$ by $0.008$ .

$1 - 150 \cdot {0.2}^{2} + 45 \cdot 0.2 - 4$

Step 10.18.1.3.4

Raise $0.2$ to the power of $2$ .

$1 - 150 \cdot 0.04 + 45 \cdot 0.2 - 4$

Step 10.18.1.3.5

Multiply $- 150$ by $0.04$ .

$1 - 6 + 45 \cdot 0.2 - 4$

Step 10.18.1.3.6

Subtract $6$ from $1$ .

$- 5 + 45 \cdot 0.2 - 4$

Step 10.18.1.3.7

Multiply $45$ by $0.2$ .

$- 5 + 9 - 4$

Step 10.18.1.3.8

Add $- 5$ and $9$ .

$4 - 4$

Step 10.18.1.3.9

Subtract $4$ from $4$ .

$0$

Step 10.18.1.4

Since $0.2$ is a known root, divide the polynomial by $5 a - 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{125 a^{3} - 150 a^{2} + 45 a - 4}{5 a - 1}$

Step 10.18.1.5

Divide $125 a^{3} - 150 a^{2} + 45 a - 4$ by $5 a - 1$ .

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Step 10.18.1.5.1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$5 a$

$1$

$125 a^{3}$

$150 a^{2}$

$45 a$

$4$

Step 10.18.1.5.2

Divide the highest order term in the dividend $125 a^{3}$ by the highest order term in divisor $5 a$ .

					$25 a^{2}$
	$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$

Step 10.18.1.5.3

Multiply the new quotient term by the divisor.

				$25 a^{2}$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			+	$125 a^{3}$	-	$25 a^{2}$

Step 10.18.1.5.4

The expression needs to be subtracted from the dividend, so change all the signs in $125 a^{3} - 25 a^{2}$

				$25 a^{2}$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$

Step 10.18.1.5.5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$25 a^{2}$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$

Step 10.18.1.5.6

Pull the next terms from the original dividend down into the current dividend.

				$25 a^{2}$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$

Step 10.18.1.5.7

Divide the highest order term in the dividend $- 125 a^{2}$ by the highest order term in divisor $5 a$ .

				$25 a^{2}$	-	$25 a$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$

Step 10.18.1.5.8

Multiply the new quotient term by the divisor.

				$25 a^{2}$	-	$25 a$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					-	$125 a^{2}$	+	$25 a$

Step 10.18.1.5.9

The expression needs to be subtracted from the dividend, so change all the signs in $- 125 a^{2} + 25 a$

				$25 a^{2}$	-	$25 a$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$

Step 10.18.1.5.10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$25 a^{2}$	-	$25 a$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$
							+	$20 a$

Step 10.18.1.5.11

Pull the next terms from the original dividend down into the current dividend.

				$25 a^{2}$	-	$25 a$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$
							+	$20 a$	-	$4$

Step 10.18.1.5.12

Divide the highest order term in the dividend $20 a$ by the highest order term in divisor $5 a$ .

				$25 a^{2}$	-	$25 a$	+	$4$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$
							+	$20 a$	-	$4$

Step 10.18.1.5.13

Multiply the new quotient term by the divisor.

				$25 a^{2}$	-	$25 a$	+	$4$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$
							+	$20 a$	-	$4$
							+	$20 a$	-	$4$

Step 10.18.1.5.14

The expression needs to be subtracted from the dividend, so change all the signs in $20 a - 4$

				$25 a^{2}$	-	$25 a$	+	$4$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$
							+	$20 a$	-	$4$
							-	$20 a$	+	$4$

Step 10.18.1.5.15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$25 a^{2}$	-	$25 a$	+	$4$
$5 a$	-	$1$		$125 a^{3}$	-	$150 a^{2}$	+	$45 a$	-	$4$
			-	$125 a^{3}$	+	$25 a^{2}$
					-	$125 a^{2}$	+	$45 a$
					+	$125 a^{2}$	-	$25 a$
							+	$20 a$	-	$4$
							-	$20 a$	+	$4$
										$0$

Step 10.18.1.5.16

Since the remander is $0$ , the final answer is the quotient.

$25 a^{2} - 25 a + 4$

Step 10.18.1.6

Write $125 a^{3} - 150 a^{2} + 45 a - 4$ as a set of factors.

$\frac{(5 a - 1) (25 a^{2} - 25 a + 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.2

Factor by grouping.

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Step 10.18.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 25 \cdot 4 = 100$ and whose sum is $b = - 25$ .

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Step 10.18.2.1.1

Factor $- 25$ out of $- 25 a$ .

$\frac{(5 a - 1) (25 a^{2} - 25 (a) + 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.2.1.2

Rewrite $- 25$ as $- 5$ plus $- 20$

$\frac{(5 a - 1) (25 a^{2} + (- 5 - 20) a + 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.2.1.3

Apply the distributive property.

$\frac{(5 a - 1) (25 a^{2} - 5 a - 20 a + 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.2.2

Factor out the greatest common factor from each group.

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Step 10.18.2.2.1

Group the first two terms and the last two terms.

$\frac{(5 a - 1) ((25 a^{2} - 5 a) - 20 a + 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.2.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{(5 a - 1) (5 a (5 a - 1) - 4 (5 a - 1))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.2.3

Factor the polynomial by factoring out the greatest common factor, $5 a - 1$ .

$\frac{(5 a - 1) ((5 a - 1) (5 a - 4))}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

$\frac{(5 a - 1) (5 a - 1) (5 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.3

Combine like factors.

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Step 10.18.3.1

Raise $5 a - 1$ to the power of $1$ .

$\frac{{(5 a - 1)}^{1} (5 a - 1) (5 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.3.2

Raise $5 a - 1$ to the power of $1$ .

$\frac{{(5 a - 1)}^{1} {(5 a - 1)}^{1} (5 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.3.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{{(5 a - 1)}^{1 + 1} (5 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 10.18.3.4

Add $1$ and $1$ .

$\frac{{(5 a - 1)}^{2} (5 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 11

Reduce the expression by cancelling the common factors.

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Step 11.1

Cancel the common factor of ${(5 a - 1)}^{2}$ .

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Step 11.1.1

Cancel the common factor.

$\frac{{(5 a - 1)}^{2} (5 a - 4)}{{(5 a - 1)}^{2} (5 a + 1) (5 a - 4)}$

Step 11.1.2

Rewrite the expression.

$\frac{5 a - 4}{(5 a + 1) (5 a - 4)}$

Step 11.2

Cancel the common factor of $5 a - 4$ .

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Step 11.2.1

Cancel the common factor.

$\frac{5 a - 4}{(5 a + 1) (5 a - 4)}$

Step 11.2.2

Rewrite the expression.

$\frac{1}{5 a + 1}$