Basic Math Examples

$\frac{1}{5}$ , $\frac{14}{15}$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{\frac{1}{5} + \frac{14}{15}}{2}$

Step 2

Simplify the numerator.

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Step 2.1

To write $\frac{1}{5}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{\frac{1}{5} \cdot \frac{3}{3} + \frac{14}{15}}{2}$

Step 2.2

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.2.1

Multiply $\frac{1}{5}$ by $\frac{3}{3}$ .

$\frac{\frac{3}{5 \cdot 3} + \frac{14}{15}}{2}$

Step 2.2.2

Multiply $5$ by $3$ .

$\frac{\frac{3}{15} + \frac{14}{15}}{2}$

Step 2.3

Combine the numerators over the common denominator.

$\frac{\frac{3 + 14}{15}}{2}$

Step 2.4

Add $3$ and $14$ .

$\frac{\frac{17}{15}}{2}$

Step 3

Multiply the numerator by the reciprocal of the denominator.

$\frac{17}{15} \cdot \frac{1}{2}$

Step 4

Multiply $\frac{17}{15} \cdot \frac{1}{2}$ .

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Step 4.1

Multiply $\frac{17}{15}$ by $\frac{1}{2}$ .

$\frac{17}{15 \cdot 2}$

Step 4.2

Multiply $15$ by $2$ .

$\frac{17}{30}$

Step 5

Divide.

$0.5\overline{6}$

Step 6

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$0.6$