Basic Math Examples

8.5

$8.5$ ,

7.5

$7.5$ ,

7

$7$ ,

6

$6$ ,

8.5

$8.5$ ,

9.5

$9.5$ ,

10

$10$ ,

13

$13$ ,

10

$10$ ,

11.5

$11.5$ ,

10

$10$ ,

12

$12$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

\frac{8.5 + 7.5 + 7 + 6 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{8.5 + 7.5 + 7 + 6 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2

Simplify the numerator.

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Step 2.1

Add

8.5

$8.5$ and

7.5

$7.5$ .

\frac{16 + 7 + 6 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{16 + 7 + 6 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2.2

Add

16

$16$ and

7

$7$ .

\frac{23 + 6 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{23 + 6 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2.3

Add

23

$23$ and

6

$6$ .

\frac{29 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{29 + 8.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2.4

Add

29

$29$ and

8.5

$8.5$ .

\frac{37.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{37.5 + 9.5 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2.5

Add

37.5

$37.5$ and

9.5

$9.5$ .

\frac{47 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{47 + 10 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2.6

Add

47

$47$ and

10

$10$ .

\frac{57 + 13 + 10 + 11.5 + 10 + 12}{12}

$\frac{57 + 13 + 10 + 11.5 + 10 + 12}{12}$

Step 2.7

Add

57

$57$ and

13

$13$ .

\frac{70 + 10 + 11.5 + 10 + 12}{12}

$\frac{70 + 10 + 11.5 + 10 + 12}{12}$

Step 2.8

Add

70

$70$ and

10

$10$ .

\frac{80 + 11.5 + 10 + 12}{12}

$\frac{80 + 11.5 + 10 + 12}{12}$

Step 2.9

Add

80

$80$ and

11.5

$11.5$ .

\frac{91.5 + 10 + 12}{12}

$\frac{91.5 + 10 + 12}{12}$

Step 2.10

Add

91.5

$91.5$ and

10

$10$ .

\frac{101.5 + 12}{12}

$\frac{101.5 + 12}{12}$

Step 2.11

Add

101.5

$101.5$ and

12

$12$ .

\frac{113.5}{12}

$\frac{113.5}{12}$

\frac{113.5}{12}

$\frac{113.5}{12}$

Step 3

Divide

113.5

$113.5$ by

12

$12$ .

9.458 ¯ 3

$9.458\overline{3}$

Step 4

Divide.

9.458 ¯ 3

$9.458\overline{3}$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

9.5

$9.5$