Basic Math Examples

$\frac{2}{5}$ , $\frac{3}{10}$ , $\frac{1}{10}$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{\frac{2}{5} + \frac{3}{10} + \frac{1}{10}}{3}$

Step 2

Simplify the numerator.

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Step 2.1

To write $\frac{2}{5}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{\frac{2}{5} \cdot \frac{2}{2} + \frac{3}{10} + \frac{1}{10}}{3}$

Step 2.2

Write each expression with a common denominator of $10$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.2.1

Multiply $\frac{2}{5}$ by $\frac{2}{2}$ .

$\frac{\frac{2 \cdot 2}{5 \cdot 2} + \frac{3}{10} + \frac{1}{10}}{3}$

Step 2.2.2

Multiply $5$ by $2$ .

$\frac{\frac{2 \cdot 2}{10} + \frac{3}{10} + \frac{1}{10}}{3}$

Step 2.3

Combine the numerators over the common denominator.

$\frac{\frac{2 \cdot 2 + 3}{10} + \frac{1}{10}}{3}$

Step 2.4

Simplify the numerator.

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Step 2.4.1

Multiply $2$ by $2$ .

$\frac{\frac{4 + 3}{10} + \frac{1}{10}}{3}$

Step 2.4.2

Add $4$ and $3$ .

$\frac{\frac{7}{10} + \frac{1}{10}}{3}$

Step 2.5

Combine the numerators over the common denominator.

$\frac{\frac{7 + 1}{10}}{3}$

Step 2.6

Add $7$ and $1$ .

$\frac{\frac{8}{10}}{3}$

Step 2.7

Cancel the common factor of $8$ and $10$ .

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Step 2.7.1

Factor $2$ out of $8$ .

$\frac{\frac{2 (4)}{10}}{3}$

Step 2.7.2

Cancel the common factors.

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Step 2.7.2.1

Factor $2$ out of $10$ .

$\frac{\frac{2 \cdot 4}{2 \cdot 5}}{3}$

Step 2.7.2.2

Cancel the common factor.

$\frac{\frac{2 \cdot 4}{2 \cdot 5}}{3}$

Step 2.7.2.3

Rewrite the expression.

$\frac{\frac{4}{5}}{3}$

Step 3

Multiply the numerator by the reciprocal of the denominator.

$\frac{4}{5} \cdot \frac{1}{3}$

Step 4

Multiply $\frac{4}{5} \cdot \frac{1}{3}$ .

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Step 4.1

Multiply $\frac{4}{5}$ by $\frac{1}{3}$ .

$\frac{4}{5 \cdot 3}$

Step 4.2

Multiply $5$ by $3$ .

$\frac{4}{15}$

Step 5

Divide.

$0.2\overline{6}$

Step 6

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$0.3$