Basic Math Examples

$8.6$ , $4.6$ , $7.9$ , $6.1$ , $2.3$ , $2.1$ , $8.5$ , $6.3$ , $7.6$ , $4.4$ , $3.4$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{8.6 + 4.6 + 7.9 + 6.1 + 2.3 + 2.1 + 8.5 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2

Simplify the numerator.

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Step 2.1

Add $8.6$ and $4.6$ .

$\frac{13.2 + 7.9 + 6.1 + 2.3 + 2.1 + 8.5 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2.2

Add $13.2$ and $7.9$ .

$\frac{21.1 + 6.1 + 2.3 + 2.1 + 8.5 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2.3

Add $21.1$ and $6.1$ .

$\frac{27.2 + 2.3 + 2.1 + 8.5 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2.4

Add $27.2$ and $2.3$ .

$\frac{29.5 + 2.1 + 8.5 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2.5

Add $29.5$ and $2.1$ .

$\frac{31.6 + 8.5 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2.6

Add $31.6$ and $8.5$ .

$\frac{40.1 + 6.3 + 7.6 + 4.4 + 3.4}{11}$

Step 2.7

Add $40.1$ and $6.3$ .

$\frac{46.4 + 7.6 + 4.4 + 3.4}{11}$

Step 2.8

Add $46.4$ and $7.6$ .

$\frac{54 + 4.4 + 3.4}{11}$

Step 2.9

Add $54$ and $4.4$ .

$\frac{58.4 + 3.4}{11}$

Step 2.10

Add $58.4$ and $3.4$ .

$\frac{61.8}{11}$

Step 3

Divide $61.8$ by $11$ .

$5.6\overline{18}$

Step 4

Divide.

$5.6\overline{18}$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$5.62$