Basic Math Examples

79

$79$ ,

81

$81$ ,

92

$92$ ,

77

$77$ ,

92

$92$ ,

82

$82$ ,

82

$82$ ,

78

$78$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

\frac{79 + 81 + 92 + 77 + 92 + 82 + 82 + 78}{8}

$\frac{79 + 81 + 92 + 77 + 92 + 82 + 82 + 78}{8}$

Step 2

Simplify the numerator.

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Step 2.1

Add

79

$79$ and

81

$81$ .

\frac{160 + 92 + 77 + 92 + 82 + 82 + 78}{8}

$\frac{160 + 92 + 77 + 92 + 82 + 82 + 78}{8}$

Step 2.2

Add

160

$160$ and

92

$92$ .

\frac{252 + 77 + 92 + 82 + 82 + 78}{8}

$\frac{252 + 77 + 92 + 82 + 82 + 78}{8}$

Step 2.3

Add

252

$252$ and

77

$77$ .

\frac{329 + 92 + 82 + 82 + 78}{8}

$\frac{329 + 92 + 82 + 82 + 78}{8}$

Step 2.4

Add

329

$329$ and

92

$92$ .

\frac{421 + 82 + 82 + 78}{8}

$\frac{421 + 82 + 82 + 78}{8}$

Step 2.5

Add

421

$421$ and

82

$82$ .

\frac{503 + 82 + 78}{8}

$\frac{503 + 82 + 78}{8}$

Step 2.6

Add

503

$503$ and

82

$82$ .

\frac{585 + 78}{8}

$\frac{585 + 78}{8}$

Step 2.7

Add

585

$585$ and

78

$78$ .

\frac{663}{8}

$\frac{663}{8}$

\frac{663}{8}

$\frac{663}{8}$

Step 3

Divide.

82.875

$82.875$

Step 4

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

82.9

$82.9$