Basic Math Examples



\begin{array}{r} r = & 1 \end{array}

$\begin{array}{r} r = & 1 \end{array}$

Step 1

The volume of a sphere is equal to

\frac{4}{3}

$\frac{4}{3}$ times Pi

π

$π$ times the radius cubed.

\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}

$\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}$

Step 2

Substitute the value of the radius

r = 1

$r = 1$ into the formula to find the volume of the sphere. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

\frac{4}{3} \cdot π \cdot 1^{3}

$\frac{4}{3} \cdot π \cdot 1^{3}$

Step 3

Combine

\frac{4}{3}

$\frac{4}{3}$ and

π

$π$ .

\frac{4 π}{3} \cdot 1^{3}

$\frac{4 π}{3} \cdot 1^{3}$

Step 4

Simplify the expression.

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Step 4.1

One to any power is one.

\frac{4 π}{3} \cdot 1

$\frac{4 π}{3} \cdot 1$

Step 4.2

Multiply

\frac{4 π}{3}

$\frac{4 π}{3}$ by

1

$1$ .

\frac{4 π}{3}

$\frac{4 π}{3}$

\frac{4 π}{3}

$\frac{4 π}{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

\frac{4 π}{3}

$\frac{4 π}{3}$

Decimal Form:

4.18879020 \dots

$4.18879020 \dots$



\begin{array}{r} r = & 1 \end{array}

$\begin{array}{r} r = & 1 \end{array}$

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