Basic Math Examples

$\frac{2 x + 2}{10^{2} + 16 x + 6}$

Step 1

Factor $2$ out of $2 x + 2$ .

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Step 1.1

Factor $2$ out of $2 x$ .

$\frac{2 (x) + 2}{10^{2} + 16 x + 6}$

Step 1.2

Factor $2$ out of $2$ .

$\frac{2 (x) + 2 (1)}{10^{2} + 16 x + 6}$

Step 1.3

Factor $2$ out of $2 (x) + 2 (1)$ .

$\frac{2 (x + 1)}{10^{2} + 16 x + 6}$

$\frac{2 (x + 1)}{10^{2} + 16 x + 6}$

Step 2

Simplify the denominator.

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Step 2.1

Let $u = x$ . Substitute $u$ for all occurrences of $x$ .

$\frac{2 (x + 1)}{16 u + 106}$

Step 2.2

Factor $2$ out of $16 u + 106$ .

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Step 2.2.1

Factor $2$ out of $16 u$ .

$\frac{2 (x + 1)}{2 (8 u) + 106}$

Step 2.2.2

Factor $2$ out of $106$ .

$\frac{2 (x + 1)}{2 (8 u) + 2 (53)}$

Step 2.2.3

Factor $2$ out of $2 (8 u) + 2 (53)$ .

$\frac{2 (x + 1)}{2 (8 u + 53)}$

$\frac{2 (x + 1)}{2 (8 u + 53)}$

Step 2.3

Replace all occurrences of $u$ with $x$ .

$\frac{2 (x + 1)}{2 (8 x + 53)}$

$\frac{2 (x + 1)}{2 (8 x + 53)}$

Step 3

Cancel the common factor of $2$ .

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Step 3.1

Cancel the common factor.

$\frac{2 (x + 1)}{2 (8 x + 53)}$

Step 3.2

Rewrite the expression.

$\frac{x + 1}{8 x + 53}$

$\frac{x + 1}{8 x + 53}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$