Enter a problem...
Basic Math Examples
5√2-15√2−1
Step 1
Multiply 5√2-15√2−1 by √2+1√2+1√2+1√2+1.
5√2-1⋅√2+1√2+15√2−1⋅√2+1√2+1
Step 2
Multiply 5√2-15√2−1 by √2+1√2+1√2+1√2+1.
5(√2+1)(√2-1)(√2+1)5(√2+1)(√2−1)(√2+1)
Step 3
Expand the denominator using the FOIL method.
5(√2+1)√22+√2-√2-15(√2+1)√22+√2−√2−1
Step 4
Simplify.
5(√2+1)15(√2+1)1
Step 5
Divide 5(√2+1)5(√2+1) by 11.
5(√2+1)5(√2+1)
Step 6
Apply the distributive property.
5√2+5⋅15√2+5⋅1
Step 7
Multiply 55 by 11.
5√2+55√2+5
Step 8
The result can be shown in multiple forms.
Exact Form:
5√2+55√2+5
Decimal Form:
12.07106781…12.07106781…