Basic Math Examples

$- (6 p^{2} - q - 4) + (3 - p^{2} - 9 q)$

Step 1

Remove parentheses.

$- (6 p^{2} - q - 4) + 3 - p^{2} - 9 q$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$- (6 p^{2}) - - q - - 4 + 3 - p^{2} - 9 q$

Step 2.2

Simplify.

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Step 2.2.1

Multiply $6$ by $- 1$ .

$- 6 p^{2} - - q - - 4 + 3 - p^{2} - 9 q$

Step 2.2.2

Multiply $- - q$ .

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Step 2.2.2.1

Multiply $- 1$ by $- 1$ .

$- 6 p^{2} + 1 q - - 4 + 3 - p^{2} - 9 q$

Step 2.2.2.2

Multiply $q$ by $1$ .

$- 6 p^{2} + q - - 4 + 3 - p^{2} - 9 q$

$- 6 p^{2} + q - - 4 + 3 - p^{2} - 9 q$

Step 2.2.3

Multiply $- 1$ by $- 4$ .

$- 6 p^{2} + q + 4 + 3 - p^{2} - 9 q$

$- 6 p^{2} + q + 4 + 3 - p^{2} - 9 q$

$- 6 p^{2} + q + 4 + 3 - p^{2} - 9 q$

Step 3

Simplify by adding terms.

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Step 3.1

Subtract $p^{2}$ from $- 6 p^{2}$ .

$- 7 p^{2} + q + 4 + 3 - 9 q$

Step 3.2

Subtract $9 q$ from $q$ .

$- 7 p^{2} - 8 q + 4 + 3$

Step 3.3

Add $4$ and $3$ .

$- 7 p^{2} - 8 q + 7$

$- 7 p^{2} - 8 q + 7$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$