Basic Math Examples

$\frac{a^{3 + 125}}{a^{2} - 64} \div \frac{a^{3} - 5 a^{2} + 25 a}{a^{2} + a - 56}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$\frac{a^{3 + 125}}{a^{2} - 64} \cdot \frac{a^{2} + a - 56}{a^{3} - 5 a^{2} + 25 a}$

Step 2

Add $3$ and $125$ .

$\frac{a^{128}}{a^{2} - 64} \cdot \frac{a^{2} + a - 56}{a^{3} - 5 a^{2} + 25 a}$

Step 3

Simplify the denominator.

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Step 3.1

Rewrite $64$ as $8^{2}$ .

$\frac{a^{128}}{a^{2} - 8^{2}} \cdot \frac{a^{2} + a - 56}{a^{3} - 5 a^{2} + 25 a}$

Step 3.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = a$ and $b = 8$ .

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{a^{2} + a - 56}{a^{3} - 5 a^{2} + 25 a}$

Step 4

Factor $a^{2} + a - 56$ using the AC method.

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Step 4.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 56$ and whose sum is $1$ .

$- 7, 8$

Step 4.2

Write the factored form using these integers.

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{(a - 7) (a + 8)}{a^{3} - 5 a^{2} + 25 a}$

Step 5

Simplify terms.

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Step 5.1

Factor $a$ out of $a^{3} - 5 a^{2} + 25 a$ .

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Step 5.1.1

Factor $a$ out of $a^{3}$ .

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{(a - 7) (a + 8)}{a \cdot a^{2} - 5 a^{2} + 25 a}$

Step 5.1.2

Factor $a$ out of $- 5 a^{2}$ .

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{(a - 7) (a + 8)}{a \cdot a^{2} + a (- 5 a) + 25 a}$

Step 5.1.3

Factor $a$ out of $25 a$ .

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{(a - 7) (a + 8)}{a \cdot a^{2} + a (- 5 a) + a \cdot 25}$

Step 5.1.4

Factor $a$ out of $a \cdot a^{2} + a (- 5 a)$ .

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{(a - 7) (a + 8)}{a (a^{2} - 5 a) + a \cdot 25}$

Step 5.1.5

Factor $a$ out of $a (a^{2} - 5 a) + a \cdot 25$ .

$\frac{a^{128}}{(a + 8) (a - 8)} \cdot \frac{(a - 7) (a + 8)}{a (a^{2} - 5 a + 25)}$

Step 5.2

Combine.

$\frac{a^{128} ((a - 7) (a + 8))}{(a + 8) (a - 8) (a (a^{2} - 5 a + 25))}$

Step 5.3

Cancel the common factor of $a^{128}$ and $a$ .

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Step 5.3.1

Factor $a$ out of $a^{128} ((a - 7) (a + 8))$ .

$\frac{a (a^{127} ((a - 7) (a + 8)))}{(a + 8) (a - 8) (a (a^{2} - 5 a + 25))}$

Step 5.3.2

Cancel the common factors.

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Step 5.3.2.1

Factor $a$ out of $(a + 8) (a - 8) (a (a^{2} - 5 a + 25))$ .

$\frac{a (a^{127} ((a - 7) (a + 8)))}{a ((a + 8) (a - 8) (a^{2} - 5 a + 25))}$

Step 5.3.2.2

Cancel the common factor.

$\frac{a (a^{127} ((a - 7) (a + 8)))}{a ((a + 8) (a - 8) (a^{2} - 5 a + 25))}$

Step 5.3.2.3

Rewrite the expression.

$\frac{a^{127} ((a - 7) (a + 8))}{(a + 8) (a - 8) (a^{2} - 5 a + 25)}$

Step 5.4

Cancel the common factor of $a + 8$ .

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Step 5.4.1

Cancel the common factor.

$\frac{a^{127} ((a - 7) (a + 8))}{(a + 8) (a - 8) (a^{2} - 5 a + 25)}$

Step 5.4.2

Rewrite the expression.

$\frac{a^{127} (a - 7)}{(a - 8) (a^{2} - 5 a + 25)}$