Basic Math Examples

$8 (\frac{3}{4} p - \frac{1}{2} q)$

Step 1

Simplify each term.

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Step 1.1

Combine $\frac{3}{4}$ and $p$ .

$8 (\frac{3 p}{4} - \frac{1}{2} q)$

Step 1.2

Combine $q$ and $\frac{1}{2}$ .

$8 (\frac{3 p}{4} - \frac{q}{2})$

$8 (\frac{3 p}{4} - \frac{q}{2})$

Step 2

Simplify terms.

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Step 2.1

Apply the distributive property.

$8 \frac{3 p}{4} + 8 (- \frac{q}{2})$

Step 2.2

Cancel the common factor of $4$ .

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Step 2.2.1

Factor $4$ out of $8$ .

$4 (2) \frac{3 p}{4} + 8 (- \frac{q}{2})$

Step 2.2.2

Cancel the common factor.

$4 \cdot 2 \frac{3 p}{4} + 8 (- \frac{q}{2})$

Step 2.2.3

Rewrite the expression.

$2 (3 p) + 8 (- \frac{q}{2})$

$2 (3 p) + 8 (- \frac{q}{2})$

Step 2.3

Multiply $3$ by $2$ .

$6 p + 8 (- \frac{q}{2})$

Step 2.4

Cancel the common factor of $2$ .

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Step 2.4.1

Move the leading negative in $- \frac{q}{2}$ into the numerator.

$6 p + 8 \frac{- q}{2}$

Step 2.4.2

Factor $2$ out of $8$ .

$6 p + 2 (4) \frac{- q}{2}$

Step 2.4.3

Cancel the common factor.

$6 p + 2 \cdot 4 \frac{- q}{2}$

Step 2.4.4

Rewrite the expression.

$6 p + 4 (- q)$

$6 p + 4 (- q)$

Step 2.5

Multiply $- 1$ by $4$ .

$6 p - 4 q$

$6 p - 4 q$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$