Basic Math Examples

$\frac{12 \div 3 \cdot (5 (2^{2} + 3^{2}))}{7 + 3 - 6^{2}}$

Step 1

Factor.

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Step 1.1

Divide $12$ by $3$ .

$\frac{4 \cdot (5 (2^{2} + 3^{2}))}{7 + 3 - 6^{2}}$

Step 1.2

Remove unnecessary parentheses.

$\frac{4 \cdot 5 (2^{2} + 3^{2})}{7 + 3 - 6^{2}}$

Step 2

Multiply $4$ by $5$ .

$\frac{20 (2^{2} + 3^{2})}{7 + 3 - 6^{2}}$

Step 3

Raise $6$ to the power of $2$ .

$\frac{20 (2^{2} + 3^{2})}{7 + 3 - 1 \cdot 36}$

Step 4

Multiply $- 1$ by $36$ .

$\frac{20 (2^{2} + 3^{2})}{7 + 3 - 36}$

Step 5

Add $7$ and $3$ .

$\frac{20 (2^{2} + 3^{2})}{10 - 36}$

Step 6

Subtract $36$ from $10$ .

$\frac{20 (2^{2} + 3^{2})}{- 26}$

Step 7

Reduce the expression $\frac{20 (2^{2} + 3^{2})}{- 26}$ by cancelling the common factors.

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Step 7.1

Factor $2$ out of $20 (2^{2} + 3^{2})$ .

$\frac{2 (10 (2^{2} + 3^{2}))}{- 26}$

Step 7.2

Factor $2$ out of $- 26$ .

$\frac{2 (10 (2^{2} + 3^{2}))}{2 (- 13)}$

Step 7.3

Cancel the common factor.

$\frac{2 (10 (2^{2} + 3^{2}))}{2 \cdot - 13}$

Step 7.4

Rewrite the expression.

$\frac{10 (2^{2} + 3^{2})}{- 13}$

Step 8

Raise $2$ to the power of $2$ .

$\frac{10 (4 + 3^{2})}{- 13}$

Step 9

Raise $3$ to the power of $2$ .

$\frac{10 (4 + 9)}{- 13}$

Step 10

Add $4$ and $9$ .

$\frac{10 \cdot 13}{- 13}$

Step 11

Reduce the expression $\frac{10 \cdot 13}{- 13}$ by cancelling the common factors.

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Step 11.1

Factor $13$ out of $10 \cdot 13$ .

$\frac{13 \cdot 10}{- 13}$

Step 11.2

Factor $13$ out of $- 13$ .

$\frac{13 \cdot 10}{13 (- 1)}$

Step 11.3

Cancel the common factor.

$\frac{13 \cdot 10}{13 \cdot - 1}$

Step 11.4

Rewrite the expression.

$\frac{10}{- 1}$

Step 12

Divide $10$ by $- 1$ .

$- 10$