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Basic Math Examples
4v2=-5v+64v2=−5v+6
Step 1
Add 5v5v to both sides of the equation.
4v2+5v=64v2+5v=6
Step 2
Subtract 66 from both sides of the equation.
4v2+5v-6=04v2+5v−6=0
Step 3
Step 3.1
For a polynomial of the form ax2+bx+cax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=4⋅-6=-24a⋅c=4⋅−6=−24 and whose sum is b=5b=5.
Step 3.1.1
Factor 55 out of 5v5v.
4v2+5(v)-6=04v2+5(v)−6=0
Step 3.1.2
Rewrite 55 as -3−3 plus 88
4v2+(-3+8)v-6=04v2+(−3+8)v−6=0
Step 3.1.3
Apply the distributive property.
4v2-3v+8v-6=04v2−3v+8v−6=0
4v2-3v+8v-6=04v2−3v+8v−6=0
Step 3.2
Factor out the greatest common factor from each group.
Step 3.2.1
Group the first two terms and the last two terms.
(4v2-3v)+8v-6=0(4v2−3v)+8v−6=0
Step 3.2.2
Factor out the greatest common factor (GCF) from each group.
v(4v-3)+2(4v-3)=0v(4v−3)+2(4v−3)=0
v(4v-3)+2(4v-3)=0v(4v−3)+2(4v−3)=0
Step 3.3
Factor the polynomial by factoring out the greatest common factor, 4v-34v−3.
(4v-3)(v+2)=0(4v−3)(v+2)=0
(4v-3)(v+2)=0(4v−3)(v+2)=0
Step 4
If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.
4v-3=04v−3=0
v+2=0v+2=0
Step 5
Step 5.1
Set 4v-34v−3 equal to 00.
4v-3=04v−3=0
Step 5.2
Solve 4v-3=04v−3=0 for vv.
Step 5.2.1
Add 33 to both sides of the equation.
4v=34v=3
Step 5.2.2
Divide each term in 4v=34v=3 by 44 and simplify.
Step 5.2.2.1
Divide each term in 4v=34v=3 by 44.
4v4=344v4=34
Step 5.2.2.2
Simplify the left side.
Step 5.2.2.2.1
Cancel the common factor of 44.
Step 5.2.2.2.1.1
Cancel the common factor.
4v4=34
Step 5.2.2.2.1.2
Divide v by 1.
v=34
v=34
v=34
v=34
v=34
v=34
Step 6
Step 6.1
Set v+2 equal to 0.
v+2=0
Step 6.2
Subtract 2 from both sides of the equation.
v=-2
v=-2
Step 7
The final solution is all the values that make (4v-3)(v+2)=0 true.
v=34,-2
Step 8
The result can be shown in multiple forms.
Exact Form:
v=34,-2
Decimal Form:
v=0.75,-2