Basic Math Examples

Solve for n |3n-3|=6
|3n-3|=6|3n3|=6
Step 1
Remove the absolute value term. This creates a ±± on the right side of the equation because |x|=±x|x|=±x.
3n-3=±63n3=±6
Step 2
The complete solution is the result of both the positive and negative portions of the solution.
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Step 2.1
First, use the positive value of the ±± to find the first solution.
3n-3=63n3=6
Step 2.2
Move all terms not containing nn to the right side of the equation.
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Step 2.2.1
Add 33 to both sides of the equation.
3n=6+33n=6+3
Step 2.2.2
Add 66 and 33.
3n=93n=9
3n=93n=9
Step 2.3
Divide each term in 3n=93n=9 by 33 and simplify.
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Step 2.3.1
Divide each term in 3n=93n=9 by 33.
3n3=933n3=93
Step 2.3.2
Simplify the left side.
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Step 2.3.2.1
Cancel the common factor of 33.
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Step 2.3.2.1.1
Cancel the common factor.
3n3=93
Step 2.3.2.1.2
Divide n by 1.
n=93
n=93
n=93
Step 2.3.3
Simplify the right side.
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Step 2.3.3.1
Divide 9 by 3.
n=3
n=3
n=3
Step 2.4
Next, use the negative value of the ± to find the second solution.
3n-3=-6
Step 2.5
Move all terms not containing n to the right side of the equation.
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Step 2.5.1
Add 3 to both sides of the equation.
3n=-6+3
Step 2.5.2
Add -6 and 3.
3n=-3
3n=-3
Step 2.6
Divide each term in 3n=-3 by 3 and simplify.
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Step 2.6.1
Divide each term in 3n=-3 by 3.
3n3=-33
Step 2.6.2
Simplify the left side.
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Step 2.6.2.1
Cancel the common factor of 3.
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Step 2.6.2.1.1
Cancel the common factor.
3n3=-33
Step 2.6.2.1.2
Divide n by 1.
n=-33
n=-33
n=-33
Step 2.6.3
Simplify the right side.
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Step 2.6.3.1
Divide -3 by 3.
n=-1
n=-1
n=-1
Step 2.7
The complete solution is the result of both the positive and negative portions of the solution.
n=3,-1
n=3,-1
Enter a problem...
 [x2  12  π  xdx ]